Index exceeds the number of array elements (1).
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s(1) = 100; % Start at 100
step1 = 0:1; % The step goes from 0 to 1
F1 = [25000, 100000]; %The number of simulations for the walker
for Z = 1:length(F1) %Retrieves the length of each simulation
for B = 1:F1(Z)
for L = 100:2601 % This is for the 2500 steps, and we repeat the functions from part 1
o(L) = L; % This keeps track of the time
d(L) = rand; %Retrieves a random value for the walker
if d(L) > .5
s(L) = s(L-1) + step1; %The walker steps to the right
elseif d(L) < .5
s(L) = s(L-1) - step1; %The walker steps to the left
else
s(L) = .5;
end
end
Endp(B) = s(L); %This stores the poisiton for each simulation
end
댓글 수: 7
Ameer Hamza
2020년 3월 29일
Omar, solving it depends on what you are trying to do in the code. If you got the code from someone else, then you should ask the author about this issue.
답변 (1개)
Rik
2020년 3월 29일
If you set a breakpoint just before that line you will notice the values of all your variables: s is a scalar and L has a value of 100. Then you try to do s(L-1), which will attempt to access the 99th position in s, which doesn't exist.
You should really try using the debugging tools, starting with the warnings mlint is giving you. Make sure to resolve those. If you are absolutely sure they don't apply to your specific situation you can right-click the orange underlined code and select the option to suppress the warning on that line. None of the warnings mlint is currently giving you should be ignored.
Matlab has very flexible debugging tools including breakpoints and the option to halt execution when an error has been thrown. Use them to your advantage.
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