Delete part of the third dimension for arrays that store in the cell

Hello all,

If I had just one 3d array I know I can use:

new = 3darray(:,:,2:end)

In order to delete the first number of the third dimension.

But as I have a lot of arrays that stored in the cell, I don't know how to do it automatically. Here what I tried so far:

for i= 1:numel(tmax) %if tmax is my cell that 3d arrays stored in it
    b = tmax(i,1);
    b = b(:,:,2:end);
end

But it doesn't work correctly and result me b = 1x1x0 cell

I'm sorry but as my data (even when I tried to cut just part of it) are too large to attach I just insert a picture here:

Thank you all

Answer 1

[Sindar]

to access the data in cells (rather than the cells themselves) and to store data in a new cell array, use {}

for i= 1:numel(tmax)
    % iterates through every cell of tmax, regardless of dimensions
    temp = tmax{i};
    b{i} = temp(:,:,2:end);
end
% shapes b (originally 1D) to match tmax
b = reshape(b,size(tmax));

[Stephen23]

See also: https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html