why isnt the function tf working
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why isnt the function tf working?
i keep getting error message
댓글 수: 6
Star Strider
2020년 3월 20일
Post the error message.
Type this:
ver control
in your Command Window and copy and paste the output to a Comment here.
Minh-Buu Nguyen
2020년 3월 20일
편집: Jan
2020년 11월 30일
Ameer Hamza
2020년 3월 20일
Minh-Buu, you don't have Control System Toolbox installed. You need this toolbox to use tf().
Minh-Buu Nguyen
2020년 3월 22일
Star Strider
2020년 3월 22일
That depends on the type of license you have.
What sort of license do you have? Are you using MATLAB as part of a university license or a personal license?
lounis chehrit
2021년 6월 10일
Just a question is It normal to have a transfer function like this ?
It's definied by :
Real(TF(v)) = cos(2*pi*v).
and phase is 0.
I thing that the parameter s=j*w.
So is It normal to have a real part like this? ( parameter in the cosine)
and how to get transfert function from real and image parts.
답변 (1개)
Samatha Aleti
2020년 3월 27일
5 개 추천
Hi,
If you have the licensed product “Control Systems Toolbox”, but have not installed yet, you can do as follows:
- Go to MATLAB - > HOME -> Add-Ons -> Get Add-ons -> search for “Control Systems Toolbox” -> click Install
If you do not have the product, then
- you can download the trial version for “Control Systems Toolbox” using this link:https://www.mathworks.com/products/control.html
- Check the Pricing and Licensing details here to purchase
For any support regarding purchase or License contact the sales team:
댓글 수: 4
Laurent Prea
2020년 11월 8일
Thanks. I was looking for the toolbox :)
Goar Ayrapetyan
2020년 11월 30일
Thank you so much!
Josue Huerta
2021년 3월 23일
This really helped! Thank you!
lounis chehrit
2021년 6월 10일
Just a question is It normal to have a transfer function like this ?
It's definied by :
Real(TF(v)) = cos(2*pi*v).
and phase is 0.
I thing that the parameter s=j*w.
So is It normal to have a real part like this? ( parameter in the cosine)
and how to get transfert function from real and image parts.
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