How to duplicate certain rows of a dataset (class = dataset)?

I have a dataset with 200 rows and 20 columns. I want to duplicate each row that has a depth value of 10, e.g. dataset.depth == 10, and place the duplicate row in the next row. (The reason for duplication is because I will change values in 2 of the columns of this duplicated row, but most of the column values will remain the same.) I am thinking that a for loop with an if/else statement could work.

for i=1:length(dataset.depth)
    if dataset.depth(i) == 10
DUPLICATE COMMAND HERE NEEDED
  end
end

Thanks!

[José-Luis]

I don't really understand how your data is organized. As I understand it, you have an array of structures and one of the fields is depth. In that case what do you mean by repeating rows? Or is the depth one of the columns in your matrix?

[George McFadden]

Jose-Luis, I am using a dataset array, so not a structure. Thanks for your interest, I ended up using the following code:

for i=1:286
    if aa.depth(i) == 10
        aa = [aa;aa(i,:)];
        aa=sortrows(aa,{'dpID','depth'});
        aa(i+1,7) = dataset(0);
        aa(i+1,12) = dataset(x);
        i = i + 1;        
    end    
end

Straight forward code, the important lines being aa = [aa;aa(i,:)]; which duplicates the line at i and appends to end of list; and the other important line being i = i +1, this avoids the loop duplicating the same row infinitely.

Thanks!

Answer 1

[Matt J]

No need to use for-loops at all:

B=num2cell(A,2).';  %A is 200x20
 B=[B;B];

B(2,dataset.depth~=10)={[]};

newmatrix = vertcat(B{:});

Answer 2

[Peter Perkins]

As Matt says, no need to use loops. This might be a little simpler.

First cook up some data:

aa = dataset((1:100)',randi(10,100,1),randn(100,1),'VarNames',{'dpID' 'depth' 'somethingElse'});

Then find the rows to duplicate, and put duplicates at the end:

i = (aa.depth == 10);

Then sort to put duplicates in place:

aa = sortrows([aa; aa(i,:)],'dpID');

Hope this helps.