compute from a set of parameters

C = 60; % capacity of a truck
demand = [30 35 24 15 14 48]; % goods to deliver
m = 2; % no of avaible trucks

i wanted to compute how many trucks needed to deliver the goods

and also the number of trips taken by each truck

we will take demand of each person, and check if the sum of demand is greater than the capacity of the truck,

eg: 30 + 35 > 60, in our example, yes - so cant load both to one truck

if it is greater than the capacity we can check if any other demand can fit into the truck, else we need to load the demand into a new truck

how can i compute the number of trucks used and the number of trips

from the above example, output will be

number_of_trucks_used = 2
number_of_trips = [2 1];

i.e. first truck 2 trips and second truck 1 trip

i also wanted to store the goods loaded into the truck in a cell array, and the position taken from vector demand in another cell array like

cell_array_value = { [30 15 14]  [48] ; [35 24] }
cell_array_pos = { [1 4 5] [6] ; [2 3] }

please can some one help me to solve it in a simple way

Answer 1

[Ameer Hamza]

I posted a response to your other question: https://www.mathworks.com/matlabcentral/answers/510925-how-to-split-a-vector-into-small-subvectors-based-on-condition. I am also posting the code here so that anyone coming here can find it.

N = 60;
V = [30 35 24 15 14 48];
a = mat2cell(repmat([0 1], numel(V), 1), ones(size(V)), 2);
combs = logical(combvec(a{:})'); % create all possible combinations
combs(1, :) = []; % remove a trivial combination
cost = sum(combs.*V, 2);
valid_index = cost < N;
valid_combs = combs(valid_index, :);
valid_costs = cost(valid_index);
[valid_costs, index] = sort(valid_costs, 'descend');
valid_combs = valid_combs(index, :);
optimal_combs = logical([]);
while ~isempty(valid_combs)
    current_comb = valid_combs(1,:);
    optimal_combs = [optimal_combs; current_comb];
    index = any(valid_combs(:, current_comb) == valid_combs(1, current_comb), 2);
    valid_combs(index, :) = [];
end
result = {};
for i=1:size(optimal_combs,1)
    result{i} = V(optimal_combs(i,:));
end