Hello MATLAB community,
Everything was just working when temps was a scalar; however, I couldn't figure out why my code is not giving me 3 corresponding results for the vector temps. I am expecting 3 answers such that -1 is solid, 1 is liquid and 101 is gas.
Thank you.
temps = [-1 1 101];
F = 9/5 .* temps + 32;
if F <= 32
disp(['The Fahrenheit temperature is ', num2str(F)])
disp('solid')
elseif F > 212
disp(['The Fahrenheit temperature is ',num2str(F)])
disp('gas')
elseif F < 212 && F > 32
disp(['The Fahrenheit temperature is ',num2str(F)])
disp('liquid')
end

답변 (1개)

Bhaskar R
Bhaskar R 2020년 3월 12일

3 개 추천

You are checking all values in the if conditioning, it gives pass condition if and only of all values are true, to avoid your situation use for loop to check each value of F
temps = [-1 1 101];
F = 9/5 .* temps + 32;
for ii=1:length(F)
if F(ii) <= 32
disp(['The Fahrenheit temperature is ', num2str(F(ii))])
disp('solid')
elseif F(ii) > 212
disp(['The Fahrenheit temperature is ',num2str(F(ii))])
disp('gas')
elseif F(ii) > 32 & F(ii)< 212
disp(['The Fahrenheit temperature is ',num2str(F(ii))])
disp('liquid')
end
end

댓글 수: 1

Ireedui Ganzorig
Ireedui Ganzorig 2020년 3월 12일
thank you very much. I really appreciate it.

댓글을 달려면 로그인하십시오.

카테고리

도움말 센터File Exchange에서 Develop Apps Using App Designer에 대해 자세히 알아보기

질문:

2020년 3월 12일

댓글:

2020년 3월 12일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by