How to combine two outputs of a into a single vector.

L = randi([2,5]);
lo = [1,5,10]
hi = [3,8,9]


for k = 1:length(hi)
    if hi(k(1:end))>lo(k(1:end))
        a=[lo(k):hi(k)]
    end
end
        

Answer 1

[Star Strider]

I am not certain what result you want.

Try this:

L = randi([2,5]);
lo = [1,5,10];
hi = [3,8,9];

for k = 1:length(hi)
    if hi(k(1:end))>lo(k(1:end))
        a{k}=[lo(k):hi(k)];
    end
end

[Pallav Patel]

I want it to fill in the numbers in individual elements from 1:3 and 5:8 where low is less than hi while ignoring 10:9 where lo is greater than 9. Hence an output of [1,2,3,5,6,7,8]. I intend to use it with random integers but this is a code for testing. I keep getting two outputs of vector a from the loop. a = [1,2,3] and a = [5,6,7,8]. Is there any way to get a single output of a=[1,2,3,5,6,7,8]

[Star Strider]

One way:

for k = 1:length(hi)
    if hi(k(1:end))>lo(k(1:end))
        ac{k} = [lo(k):hi(k)];
    end
end
a = [ac{:}]

another way:

a = [];
for k = 1:length(hi)
    if hi(k(1:end))>lo(k(1:end))
        a = [a, lo(k):hi(k)];
    end
end

The first method is a bit more efficient. The second ‘grows’ ‘a’ in each iteration, and is less efficient.

Choose whatever version works best for you.

[Pallav Patel]

Thank you Strider. I just started learning arrays and was trying to add them using a counter like loops withput arrays. This makes much sense. Both of them work but my book does not cover the braces function and I was unable to comprehend how it works but the second one has made itt easier to understand both methods.

[Star Strider]

As always, my pleasure!

The first one creates ‘a’ as a cell array, then converts it to a numeric array using the square brackets. See the information in the See Also section of that documentation page to learn more about them.