Find and replace in a character array

Hey, I have this character array F='(B~C) + (~AB)'. How can I assess the array to locate all the terms that has a ~ before it and replace it with a ('). So ~C should be C'. Therefore I would like F to be F=(BC') + (A'B)

Answer 1

[Walter Roberson]

F='(B~C) + (~AB)'
F = regexprep(F, '~(.)', '$1''')

Answer 2

[BobH]

See regexprep and remember that to get a single-quote it must be doubled up in the replacement string

F='(B~C) + (~AB)';
regexprep(F,'~(.)','$1''')  % ~ plus next character into that character plus single quote 
ans =
(BC') + (A'B)