Trying to find the error in logic

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Rida Memon
Rida Memon 2020년 3월 2일
댓글: Rida Memon 2020년 3월 3일
There is some problem in the logic of this code. It is supposed to segment the lungs from chest radiographs for the set threshold but it is not doing that correctly (providing same results for any threshold value).
clear; clc; close all;
%% Loading images
Threshold = 240;
raw_x_ray='ee.png';
I=imread(raw_x_ray);
figure(101);
imshow(I);
colormap(gray);
title('Grayscale X-Ray');
I=wiener2(I, [7 7]);
figure(102);
subplot(2,1,1);
imshow(I);
subplot(2,1,2);
imhist(I, 256);
a_thresh = I >= Threshold; % set this threshold
[labelImage, numberOfBlobs] = bwlabel(a_thresh);
props = regionprops(a_thresh,'all');
sortedSolidity = sort([props.Solidity], 'descend');
SB = sortedSolidity(1);
if SB == 1
binaryImage = imbinarize(I); figure(103);
imshow(binaryImage); colormap(gray);
SE = strel('square',3);
morphologicalGradient = imsubtract(imdilate(binaryImage, SE),imerode(binaryImage, SE));
mask = imbinarize(morphologicalGradient,0.03);
SE = strel('square',2);
mask = imclose(mask, SE);
mask = imfill(mask,'holes');
mask = bwareafilt(mask,2); % control number of area show
notMask = ~mask;
mask = mask | bwpropfilt(notMask,'Area',[-Inf, 5000 - eps(5000)]);
showMaskAsOverlay(0.5,mask,'r'); % you have to download app/function showMaskAsOverlay
BW2 = imfill(binaryImage,'holes');
new_image = BW2 ;
new_image(~mask) = 0; % invert background and holes
B=bwboundaries(new_image); % can only accept 2 dimensions
figure(104);
imshow(new_image);
ss = strcat('Result_',num2str(Threshold),'.mat');
save(ss,'new_image');
hold on
visboundaries(B);
im8 = im2uint8(new_image);
imwrite(im8, 'ccc.png')
end
  댓글 수: 2
Rida Memon
Rida Memon 2020년 3월 2일
The code is providing same output for any threshold value be it 90,110 or 250 etc.. I feel the problem is in these lines: SB = sortedSolidity(1); if SB == 1

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답변(1개)

Daniel Vieira
Daniel Vieira 2020년 3월 2일
편집: Daniel Vieira 2020년 3월 2일
the Threshold parameter doesn't matter at all in your code. you binarize the image with the threshold, measure solidity of blobs, take the largest solidity, and if it's 1 (which is extremely likely) then you throw the previous binarization away and binarize again with default values of imbinarize. I'm not sure that's what you intended to do, but to me it seems unntentional, I don't think this approach goes anywhere.
  댓글 수: 1
Rida Memon
Rida Memon 2020년 3월 3일
Actually i have picked that code from a site. I understand that there is above stated problem with this code. Therefore i need help to correct this code. It should not throw but use that previously obtained threshold. Kindly help me if you can.

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