how to substitute sym variables in jacobian matrix with numeric values?

조회 수: 33 (최근 30일)
Nikhil Shriyan
Nikhil Shriyan 2020년 2월 20일
답변: Devineni Aslesha 2020년 2월 24일
syms x y z
u = -Iscr + Iph - (x * ((exp((Iscr*y)/(n*Vth)))-1)) ...
- ((Iscr*y)/z);
v = Iph - (x * ((exp((Vocr)/(n*Vth)))-1)) - ((Vocr)/z);
w = -Im + Iph - (x * ((exp((Vm + Im*y)/(n*Vth)))-1))...
- ((Vm + (Im*y))/z);
a= jacobian([u;v;w],[x,y,z])
j=subs(a,[x,y,z],[xo,yo,zo]) %% This doesn't work, please explain why and also the alternative to this.

답변 (1개)

Devineni Aslesha
Devineni Aslesha 2020년 2월 24일
The ‘subs’ function works as expected. Please find the code shown below.
Iscr = 1;
Iph = 2;
Vth = 5;
n = 4;
Vocr = 3;
Im = 2;
Vm = 5;
syms x y z
u = -Iscr + Iph - (x * ((exp((Iscr*y)/(n*Vth)))-1)) ...
- ((Iscr*y)/z);
v = Iph - (x * ((exp((Vocr)/(n*Vth)))-1)) - ((Vocr)/z);
w = -Im + Iph - (x * ((exp((Vm + Im*y)/(n*Vth)))-1))...
- ((Vm + (Im*y))/z);
a = jacobian([u;v;w],[x,y,z]);
j = subs(a,[x,y,z],[1,2,3]);

카테고리

Help CenterFile Exchange에서 Calculus에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by