필터 지우기
필터 지우기

Saving values from a for loop into an existing matrix

조회 수: 2 (최근 30일)
Allen Love
Allen Love 2020년 2월 13일
댓글: Allen Love 2020년 2월 17일
Hello,
I am trying to define the boundary conditions in a FEM truss problem. I am having trouble saving what I did to the matrix. For example if BC(1) = 0 I want to make the first row equal to 0 then make the value in that row along the diagnol equal to 1 and save it to the original matrix.
here is my code:
%number of nodes / number of degrees of freedom
num_nd = 4;
num_dof = 2;
% Boundary Conditions
n_u = ones(num_nd, num_dof);
n_u(1,1) = 0; % Boundary conditions for node 1 x
n_u(1,2) = 0; % Boundary conditions for node 1 y
n_u(3,1) = 0; % Boundary condition for node 3 y
% Global matrix
kg = [1.3536 .3536 -1 0 0 0 -.3536 -.3536;
.3536 1.3536 0 0 0 -1 -.3536 -.3536;
-1 0 1 0 0 0 0 0; 0 0 0 1 0 0 0 -1;
0 0 0 0 1 0 -1 0; 0 -1 0 0 0 1 0 0;
-.3536 -.3536 0 0 -1 0 1.3536 .3536;
-.3536 -.3536 0 -1 0 0 .3536 1.3536];
%Apply boundary conditions
for i = 1:num_nd
if n_u(i) == 0
kg(i,:) = 0;
if kg(i,:) == 0
kg(i,i) = 1;
end
end
end
% What I want kg to look like
% kg = [1 0 0 0 0 0 0 0;
% 0 1 0 0 0 0 0 0;
% -1 0 1 0 0 0 0 0;
% 0 0 0 1 0 0 0 -1;
% 0 0 0 0 1 0 0 0;
% 0 -1 0 0 0 1 0 0;
% -.3536 -.3536 0 0 -1 0 1.3536 .3536;
% -.3536 -.3536 0 -1 0 0 .3536 1.3536];

답변 (1개)

Spencer Chen
Spencer Chen 2020년 2월 13일
This might be your problem:
for i = num_nd ...
This code does not give you a proper for-loop.
I'll leave you pondering on the problem yourself.
Blessings,
Spencer
  댓글 수: 2
Allen Love
Allen Love 2020년 2월 14일
even for i = 1:num_nd I still get the original matrix. I understand for loops in the basic sense. My question is how to save values to an existing matrix.
Allen Love
Allen Love 2020년 2월 17일
Any ideas beyond the for loop syntax?

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by