# Slice of a surface plot created by 2D data

조회 수: 52(최근 30일)
Mai Sakuragi 2020년 2월 9일
답변: Rajani Mishra 2020년 3월 13일
Hi, I have been trying to create a slice though my surface plot which is created with stacked 2D data.
Fs = 3000;
tspan = 0 : 1/Fs :15;
topt = 3
j = topt-1.0 : 0.05 : topt+4.0
---------------------------------------------------------------
delta_r1 = zeros(length(tspan), length(j));
delta_r2 = zeros(length(tspan), length(j));
for ii = 1:numel(j)
t_THz = j(ii);
delta_r1(:,ii) = Fourier1P - fourier1P(:,ii);
delta_r2(:,ii) = Fourier2P - fourier2P(:,ii);
end
delay = zeros(1,length(j));
for ii = 1:numel(j)
t_THz = j(ii);
delay(ii) = t_THz - topt;
end
yMat = repmat(delay, numel(tspan),1);
xMat = repmat(F1.',1,length(j));
plot3(xMat,yMat,delta_r1)
xlim([358 362.5])
zlim([-0.4e-4 2e-4])
xlabel('Frequency (THz)','Rotation', -15)
ylabel('Delay (ps)','Rotation', 23)
title('x_1(f)')
view([19.245913 34.150412])
figure
surf(xMat,yMat,delta_r1)
xlim([358.5 361.7])
zlim([-0.4e-4 2e-4])
xlabel('Frequency (THz)','Rotation',-15)
ylabel('Delay (ps)','Rotation',23)
view([40.018393 23.670967])
colormap(jet)
where
delta_r1
and
delta_r2
are 2D arrays of size 45001×101.
I want to create a slice though x = 360.9 so that I can get the side view of the oscillation.
What I have now is this:
x = linspace(358,362.5,length(tspan))
delay
[X,Y] = meshgrid(x,delay)
yq = linspace(-1,4,101)
xq = linspace(360.9,360.9,101)
zq = interp2(X,Y,delta_r1',xq,yq);
dq = sqrt((xq-360.9).^2 + (yq+1).^2);
plot(dq,zq)
axis([min(dq),max(dq),-0.4e-4,2e-4])
I get this plot
It's a straight line rather than an oscillation.
Does anyone know how to fix it?
##### 댓글 수: 1표시숨기기 없음
Thiago Henrique Gomes Lobato 2020년 2월 9일
The problem may be in your interpolation function since you're attributing different position values to your calculated results. You may try something like this:
zq = interp2(xMat,yMat,delta_r1,xq,yq);
dq = sqrt((xq-360.9).^2 + (yq+1).^2);
plot(dq,zq)

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### 답변(1개)

Rajani Mishra 2020년 3월 13일
You can try using function “slice()”, refer to this link for more information : https://www.mathworks.com/help/matlab/ref/slice.html#d118e1325646. Also I found a similar question here : https://www.mathworks.com/matlabcentral/answers/488992-how-to-take-a-horizontal-slice-of-a-3d-surface-plot

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R2018b

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