Replace cell array based on condition

i have a problem in replacing cell array based on condition

if i have

A = {[1,1,2; 2,2,3];[1,3,4; 9,6,8];[1,2,5; 2,3,4];[1,1,4; 3,4,5]};
B = [2,2,2; 3,3,3];

then, the condition that apply is when A has a value more than 5 it should be replace with B

so, the result have to be like this

result = {[1,1,2; 2,2,3];[2,2,2; 3,3,3];[1,2,5; 2,3,4];[1,1,4; 3,4,5]};

is it possible to do that ?

Thanks in advance

Answer 1

[Ioannis Andreou]

Use cellfun:

tfReplace = cellfun(@(c) any(any(c>5)), A, 'UniformOutput', true);
A{tfReplace} = B;

[Song JL]

It works!! Thank you so much !!

[Song JL]

Hi, what if i have more than one array that need to be replaced??

for example:

A = {[1,1,2; 2,2,3];[1,3,4; 9,6,8];[1,7,8; 2,3,4];[1,1,4; 8,6,5]};

and then the result should be

result = {[1,1,2; 2,2,3];[2,2,2; 3,3,3];[2,2,2; 3,3,3];[2,2,2; 3,3,3]};

i have tried to solve it using for , but i still get an error

here is my code

for r = 1:length(tfReplace)
    A{tfReplace(r)} = B;
end

seems that it isn't appropriate way..