the integer part of the division
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hello everyone
how do i get the integer part of the output of a division i.e. 23/5=4 (and the remainder is 3)
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Azzi Abdelmalek
2012년 10월 4일
편집: Azzi Abdelmalek
2012년 10월 5일
fix(23/5) % integer part
rem(23,5) % remainder
%or
mod(23,5)
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Walter Roberson
2012년 10월 5일
Consider -23/5 (that is, the case of negative numbers.) Should that be -4 times 5 and remainder -3, or should it be -5 times 5 and remainder 2 ?
If you want the -4 version so that abs() of the "integer part" of -23/5 and 23/5 are the same, then use fix()
If you want the -5 version so that the remainder is always non-negative, then use floor()
You can use either fix() or floor() if you only have positive values, with floor() being preferred (more efficient, mathematically clearer)
Do not use round() even if you have only positive values. round(23/5) is 5, not 4.
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