So I have:
s=sym('10517669');
p=nextprime(8*(S^4));
if float((p-1)/2)==(p-1)/2
...
end
I know float only works for single&double-precision, but p is so large I have to use the symbolic toolbox because it don't want to lose precision.
How could I resolve this?
THANKS

댓글 수: 2

Fangjun Jiang
Fangjun Jiang 2019년 12월 12일
p is accurately represented using sym object in your code. You know p is an integer from theory. What do you try to do? double(p) or single(p) can't represent p without precision loss.
Yuechuan Chen
Yuechuan Chen 2019년 12월 12일
편집: Yuechuan Chen 2019년 12월 12일
Oh sorry I meant p-1/2 not p...

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 채택된 답변

Walter Roberson
Walter Roberson 2019년 12월 12일

1 개 추천

if mod(p,1) == 0

추가 답변 (1개)

Fangjun Jiang
Fangjun Jiang 2019년 12월 13일

1 개 추천

If you want to check whether (p-1)/2 is an integer, then check whether p is an odd number. But since p is a prime number, it seems p is always odd except that p==2.

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질문:

2019년 12월 12일

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2019년 12월 13일

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