matlab code running problem
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I am trying to run following code on matlab 7.7.0 but it consumes too much time and No output !
for i=1:length(data);
j=1:length(data);
if y1(i)>1.2
f(j)=y1(i);
end
end
it also can not be run on matlab 6 though the developer said that it works on matlab 6.
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Daniel Shub
2012년 9월 24일
Please format your code. Are you sure your code is correct? Are you missing a for loop (over j). Can you tell use about data, y1 and f? What do you expect to see and what do you see. How long is "too much time"
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Javier
2012년 9월 24일
Hello Mali
What is the purpose of this code ??? Does the variable j change size in each iteration ? If not, do not define it. I believe that you define "j" to establish the size of f. Something that could work better:
j=size(data,1) % for column vector
If want to find the elements in y1 that are greater than 1.2
[r,c,i]=find(y1>1.2); Now you have the row, column and index value that match the search
Now you have the data, What you want to do with them ???
Hope it helps
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