can any one correct me this code please??
이전 댓글 표시
Can you correct me this code to draw the 4 axis (major axe, minor axe and the 2 diagonal and ortogonal axes) not the ellipse
bw = imread('13.jpg');
bw = bwlabel(bw);
imshow(bw)
s = regionprops(bw, 'Orientation', 'MajorAxisLength', ...
'MinorAxisLength', 'Eccentricity', 'Centroid');
phi = linspace(0,2*pi,50);
cosphi = cos(phi);
sinphi = sin(phi);
xbar = s.Centroid(1);
ybar = s.Centroid(2);
a = s.MajorAxisLength/2;
b = s.MinorAxisLength/2;
theta = pi*s.Orientation/180;
R = [ cos(theta) sin(theta)
-sin(theta) cos(theta)];
xy = [a*cosphi; b*sinphi];
xy = R*xy;
x = xy(1,:) + xbar;
y = xy(2,:) + ybar;
plot(x,y,'r','LineWidth',2);
hold off
thanks
댓글 수: 4
Azzi Abdelmalek
2012년 9월 18일
what is J on line2 ?
Pamela Paolo
2012년 9월 18일
Azzi Abdelmalek
2012년 9월 18일
what is k? have you read errors messages?
Pamela Paolo
2012년 9월 18일
답변 (4개)
bwlabel works on a 2D matrix, Your 13.jpg image is probably a color (rgb) image and hence is a 3 dimensional matrix. You could convert it to grayscale ( which is a 2d matrix)
bw2 = imread('13.jpg');
% bw2= rgb2gray(bw2); If image is binary
bw2 = bwlabel(bw2);
imshow(bw2)
s = regionprops(bw2, 'Orientation', 'MajorAxisLength', ...
'MinorAxisLength', 'Eccentricity', 'Centroid');
phi = linspace(0,2*pi,50);
cosphi = cos(phi);
sinphi = sin(phi);
xbar = s.Centroid(1);
ybar = s.Centroid(2);
a = s.MajorAxisLength/2;
b = s.MinorAxisLength/2;
theta = pi*s.Orientation/180;
R = [ cos(theta) sin(theta)
-sin(theta) cos(theta)];
xy = [a*cosphi; b*sinphi];
xy = R*xy;
x = xy(1,:) + xbar;
y = xy(2,:) + ybar;
plot(x,y,'r','LineWidth',2);
hold off
% ADDED EDIT
plot(s.Centroid(1),s.Centroid(2),'*')
line(s.Centroid(1)-a:s.Centroid(1)+a,s.Centroid(2));
line(s.Centroid(1),s.Centroid(2)-b:s.Centroid(2)+b);
댓글 수: 4
Pamela Paolo
2012년 9월 18일
Pamela Paolo
2012년 9월 18일
Image Analyst
2012년 9월 19일
I think it's because you asked for major and minor axis when what you want does not match regionprops definition of those. See my answer.
Azzi Abdelmalek
2012년 9월 18일
편집: Azzi Abdelmalek
2012년 9월 18일
The corrected code
bw = imread('13.jpg');
bw = bwlabel(bw);
imshow(bw)
s = regionprops(bw, 'Orientation', 'MajorAxisLength', ...
'MinorAxisLength', 'Eccentricity', 'Centroid');
phi = linspace(0,2*pi,50);
cosphi = cos(phi);
sinphi = sin(phi);
xbar = s.Centroid(1);
ybar = s.Centroid(2);
a = s.MajorAxisLength/2;
b = s.MinorAxisLength/2;
theta = pi*s.Orientation/180;
R = [ cos(theta) sin(theta) ;-sin(theta) cos(theta)];
xy = [a*cosphi; b*sinphi];
xy = R*xy;
x = xy(1,:) + xbar;
y = xy(2,:) + ybar;
plot(x,y,'r','LineWidth',2);
hold off
Pamela Paolo
2012년 9월 18일
0 개 추천
댓글 수: 2
Thomas
2012년 9월 19일
I have edited my code .. Please try it and see if it works..
Image Analyst
2012년 9월 19일
Pamela, people are giving you what you asked for which I don't think is what you want. See my answer.
Image Analyst
2012년 9월 19일
편집: Image Analyst
2012년 9월 19일
0 개 추천
Pamela, My guess is that you really mean Feret Diameter ( http://www.sympatec.com/Science/Characterisation/05_ParticleShape.html) rather than the major and minor axis of an ellipse fitted to the shape. Am I correct? Feret diameter will touch at least two points on the perimeter of the object, like a caliper distance, while an ellipse's axes won't necessarily have the axis endpoints on the shape's perimeter.
MATLAB does not provide Feret diameters. You can calculate it yourself using bwboundaries. Let me know if you can't figure it out. I don't have any code all ready to give you though. However, you might take a look at this File Exchange submission: http://www.mathworks.com/matlabcentral/fileexchange/30402-feret-diameter-and-oriented-box
댓글 수: 6
Pamela Paolo
2012년 9월 19일
Image Analyst
2012년 9월 19일
Then why isn't the elliptical fit working for you? Can you upload your image somewhere so we can see your objects?
Pamela Paolo
2012년 9월 19일
편집: Pamela Paolo
2013년 1월 3일
Image Analyst
2012년 9월 19일
I didn't run any of their code. Does they not draw lines along the major and minor directions? If they don't, I could help. If they do, then what's the problem? Do you not know how to chop your region up into quadrants? If you do, then what do you do with the pixels? Why don't you look at image moments: http://en.wikipedia.org/wiki/Image_moments, http://homepages.inf.ed.ac.uk/rbf/CVonline/LOCAL_COPIES/OWENS/LECT2/node3.html to determine symmetry?
Pamela Paolo
2012년 9월 19일
편집: Pamela Paolo
2012년 9월 19일
Image Analyst
2012년 9월 19일
PCA would probably be good. I don't have any PCA code to share with you, sorry.
카테고리
도움말 센터 및 File Exchange에서 Region and Image Properties에 대해 자세히 알아보기
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