how to find the equality of 2 numbers?

a e

1 1

1 2

3 2

3 2

The above is my input table. Check 'a' for the value '1'. The corresponding 'e' value differs. So, we should not consider it. Check 'a' the value of '3'. The corresponding 'e' values are same. How to develop code for this?

[Azzi Abdelmalek]

your data are what? string?,double?

[Image Analyst]

I think a and e are the column headers, so the variables named a and e are integers, but they may be of class int32, uint8, uint16, or even single or double.

[Sivakumaran Chandrasekaran]

Yes. As Image Analyst told, 'a' and 'e' are column headers... There is no '' strings'' in my input values

[Image Analyst]

Then see my answer. Also, what does "class(a)" show when you issue that command? If you want to make absolutely sure a and e are integers, wrap them in an int32() when you create them.

[Walter Roberson]

Please retag this question; see http://www.mathworks.co.uk/matlabcentral/answers/43073-a-guide-to-tags

Answer 1

[Andrei Bobrov]

AE = [a e]; %The initial array
out = AE(abs(diff(AE,1,2)) < eps(100),:);

[Sivakumaran Chandrasekaran]

Hi Andrei,Thanks. Your answer matches my requirement 90%.. for no.'2' your code works fine. Since there is a deviation in '1' it should not come. You can see the change in the value of 'e' when the value of 'a' is 1. Can you modify the code

Answer 2

[Adrian Dronca]

I think you should consider using isequal() . The function works with single, double, string.

Answer 3

[Image Analyst]

If they're integers, use ==, like

if a == e

if they're floating point, you need to check against a tolerance:

if abs(a-e) < 0.0001

See the FAQ for more info: http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F

Answer 4

[Sivakumaran Chandrasekaran]

When you go through the first two rows, you can find that the change in the values. So, '1' should be omitted. There is no change in 3rd and 4th row.. 'e' value does not gets changed. So, we can consider 'e' .

How to do this??