if i have a list of numbers and i have to use 'while' loop to determine when the list of numbers decreased by 10000 from initial value , how should i code it ?

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the cyclist
the cyclist 2019년 8월 20일
Sounds like a school assignment. Folks here will generally be happy to help if you show what you tried so far, and ask specific questions where you are stuck.
Navikesh Krishna
Navikesh Krishna 2019년 8월 20일
I tried this but this didnt work :
-while altitude < 10000
-disp(altitude(1,1))
-end
1.PNG
hint:
idx = 1;
while idx.^3 + 5*idx.^2 - 19 < 10000
idx = idx + 1;
end
disp(idx)

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AlexG
AlexG 2019년 8월 20일
편집: AlexG 2019년 8월 20일

0 개 추천

Not clear what you mean by the initial value but if you mean the first value in the list that is 10000 less than its first value then you could use:
index = find(a <= a(1) - 10000, 1);
Above, a is your vector of numbers, e.g.,
a = [1:3 -10000:0];

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Navikesh Krishna
Navikesh Krishna 2019년 8월 20일
this is my initial values given and i have to find when the values deceased by 10000
i tried : while altitude < 10000
disp(altitude(1,1))
end
but it didnt work out
1.PNG

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도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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