Replace one NAN with zero in a row vector without a loop

I have a row vector that its size is changing in each run. Some of its elements might be NAN and I want to replace those with zero.

How can I do that without need to have a loop? isnan(A) finds nan values but I need to replace and I want to avoid loop.

Answer 1

[Raj]

A(isnan(A)) = 0; % replaces NAN elements of A matrix by Zero.