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Issues with the for loop

조회 수: 1 (최근 30일)
Sophia
Sophia 2019년 8월 14일
마감: MATLAB Answer Bot 2021년 8월 20일
tt=0;
for i = 1:size(ids_2006,2) * size od ids_2006 is 212*119*177
for j = 1:size(ids_2006,3)
tt=tt+1;
i,j,tt
% size of mean_wint_rho is 119*177
% size of stdv_daily_2006 is 119*177
if (squeeze(ids_2006(tt,:,:)) < (mean_wint_rho(:,:) - 3*stdv_daily_2006(:,:)))
daily_2006 = squeeze(ids_2006(:,i,j));
new_daily_2006(tt,:,:) = daily_2006;
%size of new_daily_2006 should be 212*119*177
else
new_daily_2006(tt,:,:) = NaN;
end
end
end
I want to remove the bias from the daily dataset by removing the points that are three standard deviation from the mean.

답변 (1개)

darova
darova 2019년 8월 15일
This should work
new_daily_2006 = ids_2006*0;
for i = 1:size(ids_2006,1) %* size od ids_2006 is 212*119*177
% i,j,tt
% size of mean_wint_rho is 119*177
% size of stdv_daily_2006 is 119*177
if (squeeze(ids_2006(i,:,:)) < (mean_wint_rho(:,:) - 3*stdv_daily_2006(:,:)))
new_daily_2006(i,:,:) = squeeze(ids_2006(i,:,:));
%size of new_daily_2006 should be 212*119*177
else
new_daily_2006(i,:,:) = NaN;
end
end
The question is: when it will be work?
if (squeeze(ids_2006(i,:,:)) < (mean_wint_rho(:,:) - 3*stdv_daily_2006(:,:)))
Something like this
if ([1 0])
disp('hi')
end
Or maybe this
if any([1 0])
disp('hi')
end
  댓글 수: 3
Sophia
Sophia 2019년 9월 16일
I have finally figured the answer-
new_daily_2006 = [];
for t = 1:size(ids_2006,1)
for i = 1:size(ids_2006,2)
for j = 1:size(ids_2006,3)
temp = squeeze(ids_2006(t,i,j));
if (abs(temp) < stdv_daily_2006(i,j))
new_daily_2006(t,i,j) = temp;
else
new_daily_2006(t,i,j) = NaN;
end
end
end
end
darova
darova 2019년 9월 16일
편집: darova 2019년 9월 16일
Try also without loops
m = size(ids_2006);
temp = reshape(stdv_daily_2006,[1 size(stdv_dayly_2006)]); % make 1 x 119 x 177
cond = abs(ids_2006) < repmat(temp,[m 1 1]) % make 212 x 119 x 177
new_daily_2006(cond) = ids_2006;
new_daily_2006(~cond) = NaN;

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