I want to extract the project number from the file name
example the file fame is: 'abcdd-22_Z12'
the project number should be Z12 for sure it is dynamic name could in the next file name Z11 for intance.
which expression I should use

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per isakson
per isakson 2019년 7월 26일
편집: per isakson 2019년 7월 26일

0 개 추천

These statements
%%
chr = 'abcdd-22_Z12';
cac = regexp( chr, '(?<=_)Z\d{2}', 'match' );
cac{:}
return
ans =
'Z12'
This regex, '(?<=_)Z\d{2}', matches a literal "Z" followed by two digits, which is preceded by underscore.

추가 답변 (1개)

Walter Roberson
Walter Roberson 2019년 7월 26일

0 개 추천

[~, basename, ext] = fileparts(FileName);
parts = strsplit(basename, '_');
project = parts{end};
In some cases this can be simplified: for example if the directory and extension are already removed from FileName then
project = regexp(FileName, '(?<=_).*', 'match');

카테고리

도움말 센터File Exchange에서 File Operations에 대해 자세히 알아보기

제품

질문:

2019년 7월 26일

편집:

2019년 7월 28일

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