Error in MATLAB median inside isoutlier function
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I'm having the following error and I don't understand how to get around it. This error is on Matlab's function median when using isoutlier. My MATLAB's version is 2018b.
% Error message shown in Command Window
Error using median
Too many input arguments.
Error in locateoutliers (line 108)
center = median(a,1,'omitnan');
Error in isoutlier (line 144)
[tf, lthresh, uthresh, center] = locateoutliers(a, method, ...
I've been using this code for some time now and just recently I've been having this error. I've tried with the same data that worked before and I still obtain the same message now.
My code is basically organized in the following way:
% Data to analyze (may contain NaN)
rr = Peaks.r; % 1x900 double
% Find Outliers
out = isoutlier(rr);
When I open the line on MATLAB's intrinsic function:
% Where the error happens.
% This is MATLAB's function (obviously NOT written by me)
case 'median'
madfactor = -1 /(sqrt(2)*erfcinv(3/2)); %~1.4826
center = median(a,1,'omitnan');
amad = madfactor*median(abs(a - center), 1, 'omitnan');
lowerbound = center - p*amad;
upperbound = center + p*amad;
As I said earlier, the exact same code used to work. It's an error that is happening on MATLAB's function, so I don't know how to solve this.
I'm also havign a very similar problem with MATLAB's function normalize, and the error is on the function sum.
I didn't overwrite any function.
What can I do to fix this?
댓글 수: 2
Adam Danz
2019년 7월 9일
What version of matlab are you using (run ver())? Did the sympoms occur after changing matlab versions?
The 'omitnan' flag was introduced in r2015a. I'm wonering if an older version of matlab is accessing the median() function stored in newer release directory. This could happen if you manually moved files or added a path to a newer release directory (neither of which should ever happen).
noquinhas
2019년 7월 10일
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