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How do I update an image object in App Designer?

조회 수: 59 (최근 30일)
Gary Burton-Wilcock
Gary Burton-Wilcock 2019년 6월 28일
댓글: RITAM BASU 2022년 8월 29일
I'm using the App Designers image object to display a jpeg. The code modifies the image data and then writes it back to the jpeg. However if I reload it in the image object it uses the original jpeg - presumably cached and not updated. The only way I have found to make it use the new image is to use a different filename for the modified image and then point to the new file. The image object appears to have a reset function but trying to use it causes a 'no method' error.
  댓글 수: 4
Geoff Hayes
Geoff Hayes 2019년 6월 28일
Gary - so the only difference in the image is that you have added 25 to all elements of the app.img object? Do you see a change (in the image) when you view the updated image outside of MATLAB? Do you need to somehow refresh the app.Image?
Gary Burton-Wilcock
Gary Burton-Wilcock 2019년 6월 28일
Hi Geoff - for this example yes I'm just adding 25 just to force a change on the image. I do see the image change if, oustide Matlab, I look at the file that is written after each press of the modify button. However, pressing the reload button doesn't refresh the image in the Matlab app. It feels like Matlab has cached the original image and changing the image source property of the image control (but with a filename that it has already seen) doesn't force it to renew its data. I can't see any way to make it drop that data without restarting the app.

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Guillaume
Guillaume 2019년 6월 28일
Yes, I can observe the same behaviour. I've not been able to find exactly which class is responsible for the problem yet, it's not the Image class itself, the class mark itself as dirty every time you set the ImageSource property. It must be something else upstream that sees that the filename hasn't changed and hence do not update the display. I'll report the problem to matlab.
On the other hand, personally, I'd never give a filename to ImageSource, instead I'd passed an image array:
function readButtonPushed(app, event)
app.img = imread("lena512.bmp");
app.Image.ImageSource = repmat(app.img, 1, 1, 3); %ImageSource wants a RGB image, not a greyscale image
% the image appears in the Image control
end
% Button pushed function: modifyButton
function modifyButtonPushed(app, event)
app.img = app.img + 25;
end
% Button pushed function: reloadButton
function reloadButtonPushed(app, event)
app.Image.ImageSource = repmat(app.img, 1, 1, 3);
end
which doesn't have the same problem.
  댓글 수: 8
Image Analyst
Image Analyst 2022년 8월 29일
@RITAM BASU That's because it doesn't do anything. The output is the same as the input.
img = randi(255, 3, 3) % Create sample image.
img = 3×3
171 76 244 84 155 75 152 156 45
img2 = repmat(img, 1, 1, 1) % Do RITAM's "solution"
img2 = 3×3
171 76 244 84 155 75 152 156 45
RITAM BASU
RITAM BASU 2022년 8월 29일
Ah okay... It is exactly what I wanted. Just to open updated image every time. making it (1,1,3) gave me error mentioned by Bhisma Adhikari.
I did not fully comprehend the use of writing the 3 though. Is it to make a greyscale picture RGB ? I see that Making it 3 makes 3 copies of the same array(img2 here).
Thanks for the comment..
Have a nice day..

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