필터 지우기
필터 지우기

Linear indices from row and column indices for a rectangular region of interest.

조회 수: 13 (최근 30일)
I have the row and column indices of a rectangular region of interest in a rectangular image. How can i get the linear indices from these row and column indices?
%this works
a = rand(5,5); %changed.
row_indices = 1:5;
col_indices = 1:5;
[X,Y] = meshgrid(row_indices,col_indices);
indices = sub2ind(size(a), Y, X)
%i want the indices when rows and cols are not necessarily of same length.
a = rand(5,3); %changed
row_indices = 1:5;
col_indices = 1:3;
[X,Y] = meshgrid(row_indices,col_indices);
indices = sub2ind(size(a), Y, X) %this would give out of range subscript.
  댓글 수: 1
bayesianguy
bayesianguy 2019년 6월 16일
I had made a mistake in the code snippet. Now it is edited.
When the size of matrix is 5 x 5, the row and column indices going from 1:5 can create a nice grid which works with sub2ind.
However, when i have a rectangular matrix of size 5 x 3, the grid elements are going to have elements like (5,5) which is out of range.

댓글을 달려면 로그인하십시오.

채택된 답변

Star Strider
Star Strider 2019년 6월 16일
You need to reverse the order of the second and third arguments to sub2ind:
indices = sub2ind(size(a), X(:), Y(:)) %this would give out of range subscript.
and ideally make them column vectors, using the (:) subscript notation.
Note that ndgrid may be preferable to meshgrid.
  댓글 수: 2
bayesianguy
bayesianguy 2019년 6월 17일
It works neatly with ndgrid than meshgrid.
The vectorized input was the key. Thanks a lot.

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

KSSV
KSSV 2019년 6월 14일
편집: KSSV 2019년 6월 14일
YOu need to consider the size of matrix a.
%this works
a = rand(5,5);
row_indices = 1:5;
col_indices = 1:5;
[X,Y] = meshgrid(row_indices,col_indices);
indices = sub2ind(size(a), Y, X)
%i want the indices when rows and cols are not necessarily of same length.
row_indices = 1:5;
col_indices = 1:3;
a = rand(3,5) ;
[X,Y] = meshgrid(row_indices,col_indices);
indices = sub2ind(size(a), Y, X) %this would give out of range subscript.
  댓글 수: 1
bayesianguy
bayesianguy 2019년 6월 16일
I have made a mistake in the code snippet.
When the size of matrix is 5 x 5, the row and column indices going from 1:5 can create a nice grid which works with sub2ind.
However, when i have a rectangular matrix of size 5 x 3, the grid elements are going to have elements like (5,5) which is out of range.

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Matrices and Arrays에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by