필터 지우기
필터 지우기

Using Arrayfun for iterative plotting

조회 수: 6 (최근 30일)
Manuel Arcangeletti
Manuel Arcangeletti 2019년 5월 15일
댓글: Manuel Arcangeletti 2019년 5월 16일
Hi all,
I'm trying to plot all the elements of a cell array using the command arrayfun instead of a for loop.
My cell array is the following:
It gives me error when I use this sintax:
arrayfun(@(x)plot(repmat(x{6,2:end},1,x{2,2:end}),x{7,2:end},Gen_Array))
Can anybody please help me with this?
Thank you very much,
Manuel
  댓글 수: 4
Manuel Arcangeletti
Manuel Arcangeletti 2019년 5월 16일
James and Jan, thank you for your reply!
All I would like to do is have a really easy method to plot different things contained into my array.
For example, now I would like to have separate boxplots with,
in the first plot:
the first row af all the columns of my Gen_Array (name of my array){7,2} ,Gen_Array{7,3}, ..., Gen_Array{7,end}.
in the second plot:
the second row af all the columns of my Gen_Array (name of my array){7,2} ,Gen_Array{7,3}, ..., Gen_Array{7,end}.
and so on...
I don't know if it is possible with an arrayfun... I only tought it was the easiest way...
Thank you very much!
Manuel
Jan
Jan 2019년 5월 16일
A loop is easier to write and to debug.

댓글을 달려면 로그인하십시오.

채택된 답변

Jan
Jan 2019년 5월 16일
편집: Jan 2019년 5월 16일
For example:
for iRow = 1:2
plot(Gen_Array{7,2}(:, iRow), Gen_Array{7,3}(:, iRow));
end
I do not understand completely, what you want to plot:
"the first row af all the columns of my Gen_Array (name of my array){7,2} ,Gen_Array{7,3}, ..., Gen_Array{7,end}" - These are too many inputs for a plot() command, but maybe you can adjust me code to your needs.
arrayfun is an extremely compact method to avoid loops in the code. Internally the data are processed in loops also, so there is no real benefit for the execution. Use loops to follow the KISS concept: Keep it simple stupid.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Programming에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by