Hello! I am writing a code for a question using adaptive RK method. I encountered a problem in the while loop, where the system shows "Index Exceeds Array Bounds". I do not understand where have I gone wrong. Appreciate your help!
Note: dy_dx is a function file I wrote separately
syms dydx y x
dydx = -0.6*y + 10*(exp((-(x-2)^2)/(2*(0.075^2)))) ;
disp('The ODE for Q3 is:')
disp(dydx)
h = 0.5;
e = 0.00005;
% y(0) = 0.5
n = 0; i = 1;
x = zeros(i+1);
y = zeros(i+1);
while x(i) < 4
% y1 is the est y for full step size
k1 = zeros(i);
k1(i) = dy_dx(x(i),y(i));
k2 = zeros(i);
k2(i) = dy_dx((x(i) + (h/2)),(y(i) + (k1(i)*h/2)));
k3 = zeros(i);
k3(i) = dy_dx((x(i) + (h/2)),(y(i) + (k2(i)*h/2)));
k4 = zeros(i);
k4(i) = dy_dx((x(i) + h),(y(i) + (k3(i)*h)));
y1 = zeros(i);
y1(i) = y(i) + ((h/6)*(k1(i) + 2*k2(i) + 2*k3(i) + k4(i)));
% y2 is the est y for half step size
h_half = h/2;
k_1 = zeros(i);
k_1(i) = dy_dx(x(i),y(i));
k_2 = zeros(i);
k_2(i) = dy_dx((x(i) + (h_half/2)),(y(i) + (k_1(i)*h_half/2)));
k_3 = zeros(i);
k_3(i) = dy_dx((x(i) + (h_half/2)),(y(i) + (k_2(i)*h_half/2)));
k_4 = zeros(i);
k_4(i) = dy_dx((x(i) + h_half),(y(i) + (k_3(i)*h_half)));
y2_1 = zeros(i);
y2_1(i) = y(i) + ((h_half/6)*(k_1(i) + 2*k_2(i) + 2*k_3(i) + k_4(i)));
y(i) = y2_1(i);
x(i) = x(i) + h_half;
k_a = zeros(i);
k_a(i) = dy_dx(x(i),y(i));
k_b = zeros(i);
k_b(i) = dy_dx((x(i) + (h_half/2)),(y(i) + (k_a(i)*h_half/2)));
k_c = zeros(i);
k_c(i) = dy_dx((x(i) + (h_half/2)),(y(i) + (k_b(i)*h_half/2)));
k_d = zeros(i);
k_d(i) = dy_dx((x(i) + h_half),(y(i) + (k_c(i)*h_half)));
y2 = zeros(i);
y2(i) = y(i) + ((h_half/6)*(k_a(i) + 2*k_b(i) + 2*k_c(i) + k_d(i)));
del = y2(i) - y1(i);
E_a = del/15;
y2_new = zeros(i);
y2_new(i) = y2(i) + E_a;
err = abs(((y2_new(i) - y1(i))/y2_new(i))*100);
if err < e
break
end
y = y2_new(i);
x = x + h_half;
n = n + 1;
i = i + 1;
end
disp('The estimated y value is:')
disp(y2_new(i-1))
disp('The estimated x value is:')
disp(x(i-1))
disp('The number of iteration is:')
disp(n)
plot(x,y2_new)
hold on
plot(x,y);
legend('Half Step Size', 'Full Step Size')
xlabel('x'); ylabel('y');
title('Visual Representation of the Iteration')

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James Tursa
James Tursa 2019년 5월 14일

0 개 추천

Normally I would have expected to see code that sets the next values of x and y, but I don't see it. I.e., I am looking for lines like the following
x(i+1) = x(i) + stuff
y(i+1) = y(i) + stuff
So that when you increment i
i = i + 1;
the next values of x(i) and y(i) are available.
The way it looks to me is you increment i at the bottom of the while loop and then immediately test x(i) < 4. But the x(i) element will at some point not exist because it didn't get created in the loop.
The fix: Pre-allocate x and y properly, and set x(i+1) and y(i+1) inside your loop before incrementing i.

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LEW JUN KIT
LEW JUN KIT 2019년 5월 15일
Thank you very much, Mr. James! It's all ok now.

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