필터 지우기
필터 지우기

is there a jump of 2 months?

조회 수: 1 (최근 30일)
antonet
antonet 2012년 8월 17일
Dear all
I have the following sequence of dates
A={
'24/09/2000'
'22/10/2000'
'19/11/2000'
'17/12/2000'
'14/01/2001'
'11/02/2001'
'11/03/2001'
'08/04/2001'
'03/06/2001'
'01/07/2001'
'29/07/2001'
'26/08/2001'
'23/09/2001'
'21/10/2001'}
I want to see if I have a jump of two months. for instance, in the above example there is such a jump from '08/04/2001' to '03/06/2001'.
I am looking for an if statement
if there is not such a jump
'...'
end
thanks

채택된 답변

José-Luis
José-Luis 2012년 8월 17일
편집: José-Luis 2012년 8월 17일
Assuming your data is ordered, and that you have the financial toolbox:
numDate = datenum(A,'dd/mm/yyyy');
numDate = numDate - numDate(1);
monthNumber = month(test) + 12 * year(test);
jumpMonth = [0; diff(monthNumber)];
The vector jumpMonth will contain the difference in months between two succesive dates.
Cheers!

추가 답변 (2개)

Wayne King
Wayne King 2012년 8월 17일
The basic way to do it is using datenum()
B = datenum(A,'dd/mm/yyyy');
numdays = diff(B);
nummonths = numdays/30;
Then you need to use floor(), round(),ceil() or something similar, but you will see that only one element of nummonths is close to 2 in value
So, in this example
nummonths = ceil(nummonths);
for nn = 1:length(nummonths)
if (nummonths(nn) > 1.5 & nummonths(nn) < 3.5)
disp('There''s a jump');
else
disp('No Jump');
end
end
Anyway, you get the point.

Andrei Bobrov
Andrei Bobrov 2012년 8월 17일
[m,m] = datevec(A,'dd/mm/yyyy');
test = [0;mod(diff(m),12)] == 2;

카테고리

Help CenterFile Exchange에서 Data Type Identification에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by