Problem with XYZ points obtained

조회 수: 1 (최근 30일)
Rod Hid
Rod Hid 2019년 5월 9일
편집: Rod Hid 2019년 6월 12일
Hello,
I'm trying to get the XYZ coordenates of the world using the CameraCalibrator app from 200 segmented images obtained from the capture of an object pointed with a laser line and positioned on a platform that rotates 1.8 degrees (by capture) to subsequently generate a 3d model.
To calculate the calibration matrix with the rotation of the object, I used the following lines of code:
%%
angleX = 0;
angleY = stp*(1.8); >> stp is number of step of the platform
angleZ = 0;
Rx = rotx(angleX); Ry = roty(angleY); Rz = rotz(angleZ);
Rb = Rx*Ry*Rz;
tx = 0; ty = 0; tz = 0;
tb = [tx ty tz];
MPb = [Rb zeros(3,1); tb 1];
Rt = [RotationMatrix; TranslationVector];
MC = Rt*IntrinsicMatrix;
P = MPb*MC;
P = P';
%%
after that, with the points (u, v) obtained from the segmented image, I calculate the XYZ points of the world using the following lines of code:
%%
% (u*P31 - P11)X + (u*P32 - P12)Y + (u*P33 - P13)Z + (u*P34 - P14) = 0
% (v*P31 - P21)X + (v*P32 - P22)Y + (v*P33 - P23)Z + (v*P34 - P24) = 0
for i = 1:length([u,v]) >> this is the cycle only for an image
A = [(u(i)*P(3,1) - P(1,1)) (u(i)*P(3,2) - P(1,2)) (u(i)*P(3,3) - P(1,3));
(v(i)*P(3,1) - P(2,1)) (v(i)*P(3,2) - P(2,2)) (v(i)*P(3,3) - P(2,3))];
b = [-(u(i)*P(3,4)) + P(1,4);
-(v(i)*P(3,4)) + P(2,4)];
x = pinv(A)*b;
XYZ(i,:) = x;
end
%%
When I plot the points obtained (plot_points_XYZ.png), it doesn't resemble the real shape of the object (Cap_cam1_step_01.png).
What am I doing wrong?
Thank you for your help
Rod Hid
P.S: Are the distortion values incorporated into the calculations of the intrinsic matrix, rotation matrix and translation vector delivered by the CameraCalibrator app?
  댓글 수: 17
Rod Hid
Rod Hid 2019년 5월 17일
What is the relationship between focal length and scale?
darova
darova 2019년 5월 17일
I didn't know those are focal length. Just saw that image and tried to change fx, fy
ProjectionMatrix.jpg

댓글을 달려면 로그인하십시오.

답변 (2개)

Rod Hid
Rod Hid 2019년 5월 22일
I made a new calibration of the camera because the pattern presented some problems.
Could you help me find the new values for fx and fy that you calculated earlier for a better proportion of the object?
P.S: Attached the rotation matrix, translation vector, intrinsic matrix and an improved code of the projection matrix of the camera.
  댓글 수: 1
darova
darova 2019년 5월 23일
I dont' know how to calculate them. Just try different values

댓글을 달려면 로그인하십시오.


Rod Hid
Rod Hid 2019년 6월 12일
편집: Rod Hid 2019년 6월 12일
Is it necessary to remove the distortion from the calibration pattern to calibrate the camera and the captured images to obtain the coordinates of the laser line?

카테고리

Help CenterFile Exchange에서 Computer Vision Toolbox에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by