Help with this problem please

i want to write a script which tells me if the matrix is binary or not

the idea is to calculate the number of elements which are not equal to 0 or 1

if this number is superior to 0 that means the matrix contains at least a number superior to 1 so the matrix is not binary

if the number is equal to 0 that means the matrix contains only 0 and 1 so it's binary

so i did this

A=[0 1 2 4;1 0 3 5;0 0 2 6;4 7 8 9];

n=size(A,1);
m=size(A,2);

k=0;
for i=1:n
    for j=1:m
        if A(i,j)~= any([0;1])
            k=k+1;
        end
    end
end
if k==0
    dip('the matrix is binary');
else
    disp('the matrix is real');
end

but i don't get the desired result any help please to make this script correct ?

Answer 1

[Walter Roberson]

if ~any(A(i,j) == [0; 1])

Note that as soon as you find the first place, then you know the answer for the entire matrix, so you do not need to keep looking.

Note... there are much more efficient ways.

Question: do you need to find out whether the matrix is binary, containing only 0 and 1 values, or do you need to find out of the matrix is bi-level, containing at most two unique values? For example, some ways of representing "black and white" use 0 for black and 1 for white, but other ways of representing "black and white" use 0 for black and 255 for white.

Answer 2

[Abdelmalek Benaimeur]

Yes this what i want how to detect if the matrix contains only 0 and 1 or not