how to define binary matrix in matlab?

let's suppose that i have this matrix

A=[0001

0010;

0011;

0100;

0101]

how can i define it to matlab so that it will be reconized as binary matrix and not double ?

Answer 1

[James Tursa]

If you mean that you type in the A matrix exactly as above, but want to reinterpret the decimal digits as binary digits, then maybe something like this:

>> A=[0001
0010;
0011;
0100;
0101]
A =
     1
    10
    11
   100
   101
>> bin = reshape(sprintf('%04d',A),4,[])'
bin =
0001
0010
0011
0100
0101

If you wanted that as a logical matrix instead of a char matrix, then

bin = (bin == '1')

[Abdelmalek Benaimeur]

bin = reshape(sprintf('%04d',A),4,[])'

returns char_array i want the result in a matrix

[James Tursa]

See edited answer.

[Adam Danz]

@Abdelmalek Benaimeur

If you're looking for a numeric matrix with 0 placeholders, that's not going to happen. Even the dec2bin() function outputs a char array.

dec2bin([1:5])
ans =
  5×3 char array
    '001'
    '010'
    '011'
    '100'
    '101'

Your initial matrix "A" is already in numeric form and represents the same binary as if it had place holders.

    A =[
     1
    10
    11
   100
   101]; 
bin2dec(num2str(A))
ans =
     1
     2
     3
     4
     5
 
 bin = ['0001'
    '0010'
    '0011'
    '0100'
    '0101']; 
bin2dec(bin)
ans =
     1
     2
     3
     4
     5 

[Abdelmalek Benaimeur]

@James Tursa

You saved me

@Adam Danz

thank you a lot as well

[Abdelmalek Benaimeur]

@James Tursa

please last question

see this code

A =

     6     2     2
     3     5     1
     7     4     6
     5     8     3
     6     8     9
     3     7     9

>> bin = dec2bin(A,4)

bin =

  18×4 char array

    '0110'
    '0011'
    '0111'
    '0101'
    '0110'
    '0011'
    '0010'
    '0101'
    '0100'
    '1000'
    '1000'
    '0111'
    '0010'
    '0001'
    '0110'
    '0011'
    '1001'
    '1001'

>> bin=(bin=='1')

bin =

  18×4 logical array

   0   1   1   0
   0   0   1   1
   0   1   1   1
   0   1   0   1
   0   1   1   0
   0   0   1   1
   0   0   1   0
   0   1   0   1
   0   1   0   0
   1   0   0   0
   1   0   0   0
   0   1   1   1
   0   0   1   0
   0   0   0   1
   0   1   1   0
   0   0   1   1
   1   0   0   1
   1   0   0   1

>> bin2dec(num2str(bin))

ans =

     6
     3
     7
     5
     6
     3
     2
     5
     4
     8
     8
     7
     2
     1
     6
     3
     9
     9

how can i obtain the original matrix A in this case?

[James Tursa]

If you know the size of the original A is 6x3, then simply reshape

>> reshape(bin2dec(num2str(bin)),6,3)
ans =
     6     2     2
     3     5     1
     7     4     6
     5     8     3
     6     8     9
     3     7     9

If you don't know the size of the original A, then you are stuck because that information is not contained in the variable bin. You would need some other way to know what the variable size should be.

[Abdelmalek Benaimeur]

@James Tursa

believe me you are the best

this is for my graduation projet i will add your name as a reference

wish you all the best