As title says; I am getting a syntax error when using the following code. The error points towards the d on "end"
F0=3.18;
m=0.0112;
k=31.2;
r1=0.22;
w0=sqrt(k/m);
w=linspace(0,400,400);
r=linespace(0.11,1.1,10);
for i=1:10
x0(:,i)=(F0/m)./(sqrt(((w0^2)-(w.^2))+((j*w*r(i)/m))));
end

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Steven Lord
Steven Lord 2019년 4월 23일
Copying and pasting this code into MATLAB (after correcting the "linespace" typo, which I assume should be linspace) I did not receive an error.
Can you show us the full text of the error message (all the text displayed in red) you receive when you run this code?
Jack Upton
Jack Upton 2019년 4월 23일
It was a syntax error regarding the linspace and there was also a bracket error which I have now edited in my question.
Jack Upton
Jack Upton 2019년 4월 23일
How would I now allocate a different colour for each potted data line?
h = plot(w, x0);
will automatically use a different color or line pattern for each of the 10 lines. There are 7 default colors, so the last 3 would end up re-using the colors of the first 3, but with a different line style.
You can assign specific colors to the lines by using,
set(h(1), 'Color', [.3 .9 .2]);
set(h(2), 'Color', 'g');
set(h(3), 'Color', [1, 1/3, 7/10]);
and so on. If you have an array of color values, you can create a loop. For example,
NL = length(h);
cmap = copper( NL );
for K = 1 : NL
set(h(K), 'Color', cmap(K, :))
end
Jack Upton
Jack Upton 2019년 4월 23일
Incredible, thank you!

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madhan ravi
madhan ravi 2019년 4월 23일

0 개 추천

r = linspace... % also consider preallocating x0

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Jack Upton
Jack Upton 2019년 4월 23일
What do you mean pre-allocating x0,
sorry Im rather new to this.
Before the loop,
x0 = zeros(length(w), length(r));

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