Split one column data into 4 arrays

I have an array of 90872x1 double with 4 conditions. As follows:

A=

1

1

1

2

2

2

3

3

4

4

1

1

2

2

3

3

4

4

1

1

1

I want to split the vector into 4 arrays, one per condition. Each column of the new 4 arrays must contain de data of the conditions. Therefore.

A1=

1 1 1

1 1 1

1 1

A2=

2 2

2 2

2

A3=

3 3

3 3

A4=

4 4

4 4

Any help?

[Walter Roberson]

You cannot do that in MATLAB using numeric arrays: numeric arrays cannot have "ragged" rows or columns that have different numbers of elements than the other rows or columns.

[Francisco Anaya]

I used the following and worked well...

[C,ia,ib]=unique(B); %groups
G=length(C);
iwant=cell(G,1);
for j=1:G
    A=(B==C(j))';
    jj=zeros(size(A));
    ii=A==1;
    jj(strfind([0,ii(:)'],[0 1]))=1;
    idx=cumsum(jj).*ii;
    iwant{j}=accumarray(idx(ii)',B(ii)',[],@(x){x'});
end

[Walter Roberson]

That creates a cell array, but your question requires a numeric array as output.

Answer 1

[KSSV]

A=[1
1
1
2
2
2
3
3
4
4
1
1
2
2
3
3
4
4
1
1
1] ; 

C = unique(A) ; 
iwant = cell(length(C),1) ;
for i = 1:length(C)
    iwant{i} = A(A==C(i)) ; 
end