extrapolation of the last observation of a vector

 Dear all,
I  have

A={

 0.2560
    0.2680
    0.0504
   14.0985
    0.1128
2.5852
    0.3220
   14.0985
    2.5852
    0.2938
    0.2560
    0.2680
    0.0504
   14.0985
    0.1128
   2.5852
    0.3220
   14.0985
    2.5852
    0.2938
    0.2560
    0.2680
    0.0504
   14.0985
    0.1128
  2.5852
    0.3220
   14.0985
    2.5852
    NaN};

I want to replace the last value via extrapolation.

I tried

 inpaint_nans(cell2mat(A),2) but I got:

 Subscript indices must either be real positive integers or
logicals.

 Error in inpaint_nans (line 239)
    fda(nm,[nm,nm-1,nm-n])=[-2 1 1];

Is there any other way to replace NaN via extrapolation

thanks

[Oleg Komarov]

A suggestion, try to work with double arrays, i.e. A = [...].

inpaint_nans()

throws an error and it seems to be a bug. I just verified that it works with the transposed A:

inpaint_nans(cell2mat(A)',2)

Answer 1

[Azzi Abdelmalek]

% -----in this exemple i used a linear extrapolation ------
n=length(A);y=cell2mat(A');
x=1:n-1;xi=1:n;
yi=interp1(x,y(1:n-1),xi,'linear','extrap')

[salva]

thank you!