Using range in a vector

How do you use a loop/if statement to generate a range for vector A. Vector A can be changed by the user but the code should check if the components of the vectors are within -100 to 100

%vector A is defined as :
%A = [-10:0.5:10] ;
A = [1 2 101];
B =[]; % start with empty B

% check if the contents of A are in the range of -100 to 100
max = 100;
min = -100;

if (A>=min)|(A<=max)

    for i=[1:length(A)]
        % append cube of A(i) to B
        B = [B A(i)*A(i)*A(i)];
    end

    %display B
    disp(B);

    %display that code is invalid
else 
    fprintf("Invalid - not within range")
end

[Jos (10584)]

Did you check the output of (A>=min)|(A<=max) ?

Note that the IF statement converts this condition to a single True or False.

[madhan ravi]

madhan ravi:

fprintf('Within Range %d\n',A(A>=Min&A<=Max))
fprintf('Not Within Range %d\n',A(~(A>=Min&A<=Max)))

ck poon:

I used if A(A>=min&A<=max)

and got 1 8 1030301

but somehow im suppossed not to cube the components not within the range

madhan ravi:

A>=Min & A<=Max % index it with A and raise it to the power of three

Answer 1

[Jos (10584)]

I am a little confused by your problem, but here are my thoughts. You might want to use the function ANY, or its sibling ALL, or apply logical indexing

A = [1 2 101]

if any(A > 100)
    disp('At least one element of A is larger than 100.') ;
end

B = nan(size(A)) 
tf = A <= 100 % use logical indexing
B(tf) = A(tf) .^ 3 % only calculate cube for elements of A <= 100, other elements are NaN