How to replace array values that meet condition?

Lets say there are two arrays:

A = [3 4 5];

B = [4 6 3];

Create another matrix B_1 with the elements in B and replace some:

%if the element in matrix B, is in matrix A, it does not matter the order: take value of element in matrix B.

%if the element in matrix B, is not in matrix,A, take a random number of matrix A, that is not in matrix B.

%expected output:

%B_1= [4 5 3];

%my try

B_1=B;

A_1=A;

size_b=size(B);

random_A=A_1(randperm(length(A_1)));

for ii = 1:size_b(1,2)

if B(ii)==A

B_1(ii)=B(ii)

else

B_1(ii)=random_A(ii)

end

end

output

B_1 =

5 3 4

Answer 1

[Bob Thompson]

I'm assuming B_1 should be the same size as B? Does order matter?

If order doesn't matter:

A = [3 4 5];     
B = [4 6 3]; 
B_1 = B(ismember(B,A));
if length(B_1)<length(B)
    B_1 = [B_1, A(randperm(length(A),length(B)-length(B_1)))];
end

Whether order matters or not, you're not necessarily going to get your exact output you expect, because you're asking for a random value of A, not asking for a specific value.