Any idea why all([]) is true while any([]) is false
조회 수: 2 (최근 30일)
이전 댓글 표시
>> all([])
ans =
1
>> any([])
ans =
0
댓글 수: 2
채택된 답변
추가 답변 (1개)
the cyclist
2012년 7월 29일
I can't say I know definitively, but I expect that one reason is for consistency when taking the union of sets with the empty set. For example, one would want
all(union(true,[]))
to be true, and also
any(union(false,[]))
to be false. The definitions in your question make sense in that context.
참고 항목
카테고리
Help Center 및 File Exchange에서 Logical에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!