Solving a nonlinear ODE with derivative squared
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I'm trying to solve a nonlinear ODE which looks something like this:. I know I can use the implicit solver ode15i but the problem is also stiff so I'd prefer to use ode15s. Is it possible to solve this type of nonlinear ode using ode15s? Any suggestions would be appreciated, thank you!
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Torsten
2019년 2월 4일
As for all quadratic equations, there are two solutions for y'. Do you know which one you'll have to take ?
Bill Greene
2019년 2월 4일
ode15i is based on backward differentiation formulas so I would expect it to be as effective as ode15s for stiff problems. That has also been my experience with the two solvers. Do you have an example stiff ODE where this is not the case?
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Star Strider
2019년 2월 1일
편집: Star Strider
2019년 2월 3일
One approach:
syms a b c d y(t) T Y
Dy = diff(y);
DE = a*Dy^2 + b*Dy + c*y == d;
isoDE = isolate(DE,Dy)
[VF,Sbs] = odeToVectorField(isoDE)
odefcn = matlabFunction(VF, 'Vars',{T,Y,a b c d});
odefcn = @(T,Y,a,b,c,d)[((b+sqrt(a.*d.*4.0+b.^2-a.*c.*Y(1).*4.0)).*(-1.0./2.0))./a; ((b-sqrt(a.*d.*4.0+b.^2-a.*c.*Y(1).*4.0)).*(-1.0./2.0))./a]
a = 3;
b = 5;
c = 7;
d = 11;
[T,Y] = ode15s(@(T,Y)odefcn(T,Y,a,b,c,d), [0 5], [0;0]);
figure
plot(T, Y)
grid
It works!
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Star Strider
2019년 2월 3일
As always, my pleasure!
I‘m not sure if it’s possible express systems of PDEs in the Symbolic Math Toolbox.
You most likelly need the Partial Differential Equation Toolbox (link). I haven’t used it recently, so I have no recent experience with it.
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