필터 지우기
필터 지우기

I am trying to solve 3 simultaneous nonlinear system of equations by newton's method.

조회 수: 1 (최근 30일)
I am trying to solve 3 simultaneous nonlinear system of equations by newton's method. I am getting an error in solving that system.
The code is written below.
clear all
syms x y z
a=[1;1;1];
% The Newton-Raphson iterations starts here
del=1;
indx=0;
h=4;
gma=18.4;
ka1=0.2;
kp1=8.76;
ka2=0.2;
kp2=8.76;
sind=0.437;
cosd=0.9;
pa1=ka1*gma*(h*x+0.5*(x^2));
pp1=kp1*gma*0.5*(x^2);
pa2=ka2*gma*(x*y+0.5*(y^2));
pp2=kp2*gma*(y*(h+x)+0.5*(y^2));
za1=(0.5*h*(x^2)+(x^3)/6)/(h*x+0.5*(x^2));
zp2=(0.5*(h+x)*(y^2)+((y^3)/3))/((h+x)*y+0.5*(y^2));
za2=(0.5*x*(y^2)+((y^3)/3))+(x*y+0.5*(y^2));
e1=(pp1*sind)-(pa1*sind)-(pp2*sind)-(pa2*sind);
e2=pp1*cosd+pa2*cosd-pa1*cosd-pp2*cosd-z;
e3=pp1*cosd*(x/3)+pp2*cosd*zp2-pa1*cosd*za1-pa2*cosd*za2-z*(x+(h/3));
while del>1e-6
g=[e1; e2; e3];
J=jacobian([e1, e2, e3], [x, y, z]);
delx=-inv(J)*g;
a=a+delx;
del=max(abs(g));
indx=indx+1;
end
'NEWTON-RAPHSON SOLUTION CONVERGES IN ITERATIONS',indx,pause
'FINAL VALUES OF x ARE',x

채택된 답변

Torsten
Torsten 2019년 1월 23일
Don't use symbolic variables together with Newton-Raphson.
Instead of using "jacobian" , look at the solution suggested by John D'Errico under
https://de.mathworks.com/matlabcentral/answers/28066-numerical-jacobian-in-matlab
  댓글 수: 6
Akshay Pratap Singh
Akshay Pratap Singh 2019년 1월 24일
Thank you very much Torsten
Now, I am having one problem that the code is working fine upto h=12 and giving good results. but as I increase h to 13, 14, 15 and so on. It is giving wrong values. Your help will be highly appreciated. Thank you in advance.
The code is written below as well as attached-
clear all
syms x y z
a=[1;1;1];
format longEng
% The Newton-Raphson iterations starts here
del=1;
indx=0;
h=13;
gma=18.4;
ka1=0.2;
kp1=8.7;
ka2=0.32;
kp2=8.7;
sinda1=0.437;
sindp1=0.437;
sinda2=0.437;
sindp2=0.437;
cosda1=0.9;
cosdp1=0.9;
cosda2=0.9;
cosdp2=0.9;
pa1=ka1*gma*0.5*(x^2);
pp1=kp1*gma*0.5*(x^2);
pa2=ka2*gma*((x*y)+0.5*(y^2));
pp2=kp2*gma*((x*y)+0.5*(y^2));
za1=x/3;
zp1=x/3;
zp2=(0.5*x*(y^2)+((y^3)/3))/((x*y)+0.5*(y^2));
za2=(0.5*x*(y^2)+((y^3)/3))/((x*y)+0.5*(y^2));
e1=(pp1*sindp1)-(pa1*sinda1)-(pp2*sindp2)-(pa2*sinda2);
e2=(pp1*cosdp1)+(pa2*cosda2)-(pa1*cosda1)-(pp2*cosdp2)-z;
e3=(pp1*cosdp1*zp1)+(pp2*cosdp2*zp2)-(pa1*cosda1*za1)-(pa2*cosda2*za2)-(z*(x+h));
g=[e1; e2; e3];
J=jacobian([e1, e2, e3], [x, y, z]);
while del>1e-6
gnum = double(subs(g,[x,y,z],[a(1),a(2),a(3)]));
Jnum = double(subs(J,[x,y,z],[a(1),a(2),a(3)]));
delx = -Jnum\gnum;
a = a + delx;
del = max(abs(gnum));
indx = indx + 1;
end
'NEWTON-RAPHSON SOLUTION CONVERGES IN ITERATIONS',indx,pause
'FINAL VALUES OF a ARE',a
Torsten
Torsten 2019년 1월 24일
편집: Torsten 2019년 1월 24일
Use the result from the previous h as initial guess for the next h.
In your case:
Use
a=[1.87;0.74;17.47]; % approximate result for h=12
as initial "a" for h=13.
And I think you get faster convergence if you replace
gnum = double(subs(g,[x,y,z],[a(1),a(2),a(3)]));
Jnum = double(subs(J,[x,y,z],[a(1),a(2),a(3)]));
by
gnum = vpa(subs(g,[x,y,z],[a(1),a(2),a(3)]));
Jnum = vpa(subs(J,[x,y,z],[a(1),a(2),a(3)]));
You could try this code:
syms x y z h
a=[1;1;1];
format longEng
% The Newton-Raphson iterations starts here
H=linspace(2,30,29);
gma=18.4;
ka1=0.2;
kp1=8.7;
ka2=0.32;
kp2=8.7;
sinda1=0.437;
sindp1=0.437;
sinda2=0.437;
sindp2=0.437;
cosda1=0.9;
cosdp1=0.9;
cosda2=0.9;
cosdp2=0.9;
pa1=ka1*gma*0.5*(x^2);
pp1=kp1*gma*0.5*(x^2);
pa2=ka2*gma*((x*y)+0.5*(y^2));
pp2=kp2*gma*((x*y)+0.5*(y^2));
za1=x/3;
zp1=x/3;
zp2=(0.5*x*(y^2)+((y^3)/3))/((x*y)+0.5*(y^2));
za2=(0.5*x*(y^2)+((y^3)/3))/((x*y)+0.5*(y^2));
e1=(pp1*sindp1)-(pa1*sinda1)-(pp2*sindp2)-(pa2*sinda2);
e2=(pp1*cosdp1)+(pa2*cosda2)-(pa1*cosda1)-(pp2*cosdp2)-z;
e3=(pp1*cosdp1*zp1)+(pp2*cosdp2*zp2)-(pa1*cosda1*za1)-(pa2*cosda2*za2)-(z*(x+h));
g=[e1; e2; e3];
J=jacobian([e1, e2, e3], [x, y, z]);
A=zeros(3,numel(H));
for i=1:numel(H)
del = 1.0;
indx = 0;
while del>1e-6
gnum = vpa(subs(g,[x,y,z,h],[a(1),a(2),a(3),H(i)]));
Jnum = vpa(subs(J,[x,y,z,h],[a(1),a(2),a(3),H(i)]));
delx = -Jnum\gnum;
a = a + delx;
del = max(abs(gnum));
indx = indx + 1;
end
A(:,i)=double(a)
end
plot(H,A(3,:))

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Calculus에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by