InputParser and function handle

조회 수: 2 (최근 30일)
Anon
Anon 2012년 7월 18일
Hi,
I want to use the InputParser Class to check the inputs of a function. Basically my function looks like this
function a = myfun(b,varargin)
p = inputParser;
addRequired(p,'b',@isnumeric);
addOptional(p,'fun',@mean,@(x) isa(x,'function_handle'));
parse(p,b,varargin);
a = p.Results.fun(p.Results.b);
If I call this function, say with
a = myfun(rand(10,1),'fun',@mean)
Matlab throws an error saying
Error using myfun (line 8)
Argument 'fun' failed validation @(x)isa(x,'function_handle').
What am I doing wrong and what is the best way to pass a function handle through the inputParser?
Regards, Anon

답변 (1개)

Wolfgang
Wolfgang 2013년 3월 25일
You have to write:
parse(p,b,varargin{:});
In your case, the function handle is presented to the parser as part of a cell array (varargin) so it doesn't recognize it correctly.
  댓글 수: 1
Bjorn Gustavsson
Bjorn Gustavsson 2013년 8월 7일
(I just ran into the same problem as Anon.) That varargin is a cell-array I understand, but shouldn't varargin{:} be the list of its contens, and that list is what the parse function should see?

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Argument Definitions에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by