why the code is not running?
이전 댓글 표시
m = 0;
x = linspace(0,1,41);
t = linspace(0,200,10);
sol = pdepe(m,@pdex5pde,@pdex5ic,@pdex5bc,x,t);
n = sol(:,:,1);
c = sol(:,:,2);
figure;
surf(x,t,c);
title('Distribution of fibronectin--c(x)');
xlabel('Distance x');
ylabel('Time t');
figure;
surf(x,t,n);
title('Distribution of ECs--n(x)');
xlabel('Distance x');
ylabel('Time t');
figure;
plot(x,n(end,:));
title('Final distribution of n(x).');
figure;
plot(x,c(end,:));
title('Final distribution of c(x).');
% --------------------------------------------------------------------------
function [c,f,s] = pdex5pde(x,t,u,DuDx)
d = 1e-3;
a = 3.8;
S = 3;
r = 0.88;
N = 1;
c = [1; 1];
f = [ d*DuDx(1) - a*u(1)*DuDx(2)
DuDx(2) ];
s1 = S*r*u(1)*(N - u(1));
s2 = S*(u(1)/(u(1) + 1) - u(2));
s = [s1; s2];
% --------------------------------------------------------------------------
function u0 = pdex5ic(x)
u0 = [1; 0.5];
if x >= 0.3 & x <= 0.6
u0(1) = 1.05 * u0(1);
u0(2) = 1.0005 * u0(2);
end
댓글 수: 13
Walter Roberson
2018년 12월 20일
What error message are you getting?
madhan ravi
2018년 12월 20일
편집: madhan ravi
2018년 12월 28일
Upload pdex5bc function.
KSSV
2018년 12월 20일
YOu should specify your error or problem..so that we can help you straight away if possible. Simply copying a part of code will not help us to help you.
MINATI
2018년 12월 20일
Stephen23
2018년 12월 20일
@MINATI: please show us the output from this command:
which pdepe -all
MINATI
2018년 12월 20일
madhan ravi
2018년 12월 20일
?
Cris LaPierre
2018년 12월 20일
function pdex4
m = 0;
x = [0 0.005 0.01 0.05 0.1 0.2 0.5 0.7 0.9 0.95 0.99 0.995 1];
t = [0 0.005 0.01 0.05 0.1 0.5 1 1.5 2];
sol = pdepe(m,@pdex4pde,@pdex4ic,@pdex4bc,x,t);
u1 = sol(:,:,1);
u2 = sol(:,:,2);
figure
surf(x,t,u1)
title('u1(x,t)')
xlabel('Distance x')
ylabel('Time t')
figure
surf(x,t,u2)
title('u2(x,t)')
xlabel('Distance x')
ylabel('Time t')
% --------------------------------------------------------------
function [c,f,s] = pdex4pde(x,t,u,DuDx)
c = [1; 1];
f = [0.024; 0.17] .* DuDx;
y = u(1) - u(2);
F = exp(5.73*y)-exp(-11.47*y);
s = [-F; F];
% --------------------------------------------------------------
function u0 = pdex4ic(x);
u0 = [1; 0];
% --------------------------------------------------------------
function [pl,ql,pr,qr] = pdex4bc(xl,ul,xr,ur,t)
pl = [0; ul(2)];
ql = [1; 0];
pr = [ur(1)-1; 0];
qr = [0; 1];
If I straight borrow pdex4bc and add it to the code provided above, I get the following warnings/errors:
- Warning: Failure at t=1.269576e-02. Unable to meet integration tolerances without reducing the step size below the smallest value allowed (2.775558e-17) at time t.
- Warning: Time integration has failed. Solution is available at requested time points up to t=1.000000e-02.
- Error using surf (line 71)
- Data dimensions must agree.
madhan ravi
2018년 12월 20일
편집: madhan ravi
2018년 12월 20일
Well thank you Cris for digging into a bit deeper , @Minati just two words doesn’t explain anything , you need to explain more plus you completely ignored the comments which were latter to your comment.
MINATI
2018년 12월 27일
Walter Roberson
2018년 12월 27일
Which MATLAB release are you using?
MINATI
2018년 12월 28일
Walter Roberson
2018년 12월 28일
편집: Walter Roberson
2018년 12월 28일
What shows up for
which -all pdepe
I have tried the example in R2016b, and I tried your code (along with a copy of pdex4bc renamed pdex5bc) in R2016b, and I do not get any problem about too many input arguments for pdepe. I do get the error that Cris mentioned: with that boundary condition, your sol comes out 1 x 41 and you cannot surf() a vector.
You should post the pdex5bc that you are using.
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