what I should do-----second order variable coefficients ODE??
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Hi, matlab person,I have some problems about second order variable coefficients ODE.
Thank you very much for any suggestion or help.
equation: x^2 y''+x y'-sin(y)cos(y)+4*k/pi*x sin(y)^2-x^2 sin(y)cos(y)=0
boundary condition: y(0)=0;y'(0)=-0.126
The following is my code, but there are several problem:
first defining function *********************************************
function yprime = skyrmion(x,y)
k=0.95;
yprime = [y(2); -1/x*y(2)+1/x^2*sin(y(1))*cos(y(1))-4*k/pi* (1/x)*sin(y(1))^2+sin(y(1))*cos(y(1))];
*********************************************************
Then transfer function
*****************************************************
xspan=[0.01,10];
y0=[-0.126;pi];
[x,y]=ode45('skyrmion',xspan,y0);
plot(x(:),y(:,2))
****************************************************
problem one:
Because The ODE was divided by x^2, so the x span can't use x==0. whether the code can be modified to not divide x^2.
problem two:
the results get by using my code are not consist with some papers.
so I want to know my code is right or wrong.
댓글 수: 2
Walter Roberson
2012년 7월 14일
편집: Walter Roberson
2012년 7월 14일
To confirm: x is independent and there is y(x) ? In particular, it is not x(t) and y(t) ?
And y'' is diff(diff(y(x),x),x) ?
채택된 답변
Star Strider
2012년 7월 14일
편집: Star Strider
2012년 7월 14일
Your initial equation:
x^2 y''+x y'-sin(y)cos(y)+x sin(y)^2-x^2 sin(y)cos(y)=0
does not contain the ‘-4*k*pi’ term that appears in your second one:
yprime = [y(2); -1/x*y(2)+1/x^2*sin(y(1))*cos(y(1)) -4*k/pi * (1/x)*sin(y(1))^2+sin(y(1))*cos(y(1))];
So should
-4*k*pi
be
-4*k*pi/x^2
instead?
I found no other problems with your conversion of the first equation to your ‘yprime’ matrix expression. You could simplify it a bit by combining the ‘sin(y)*cos(y)’ terms to ‘(1+1/x^2)*sin(y)*cos(y)’ but I doubt that would make much of a performance difference.
I believe ‘ode45’ will avoid the singularity at x=0 on its own, and search for solutions elsewhere. If you want to be certain about this, contact TMW Tech Support and ask them.
댓글 수: 4
Star Strider
2012년 7월 16일
편집: Star Strider
2012년 7월 16일
My pleasure! The ‘ode45’ function is also a Runge-Kutta solver, according to the documentation. You and the authors you quote are both correct as I understand it. The behavior of the integrated differential equation is similar to that of ‘exp(-x)*cos(x)’ so while it approaches zero asymptotically for large x, it also remains periodic.
I doubt it is possible to add the boundary condition of y(x->infinity) -> 0 to ‘ode45’, although the function seems to do this itself. You might be able to do this with ‘bvp4c’. I have used ‘bvp4c’ once, so I do not feel qualified to comment on how you would apply it to your differential equation. I will experiment with it later.
추가 답변 (1개)
Walter Roberson
2012년 7월 14일
Please check my transcription of your equations:
dsolve( [x^2*((D@@2)(y))(x)+x*(D(y))(x)-sin(y(x))*cos(y(x))+x*sin(y(x))^2-x^2*sin(y(x))*cos(y(x)), (D(y))(0) = 0, ((D@@2)(y))(0) = -.126])
When I use that, Maple believes there is no solution. Indeed it thinks that even when I do not provide the boundary conditions.
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