필터 지우기
필터 지우기

Question about number format

조회 수: 3 (최근 30일)
holistic
holistic 2018년 12월 14일
댓글: holistic 2018년 12월 17일
When I calculate the eigenvectors of the following matrix:
mat=[1,2;2,1];
[V,D]=eig(mat)
I get:
V =
-0.7071 0.7071
0.7071 0.7071
However, this is not the correct answer, see Wolfram Alpha results or verify by yourself that the correct answer are the vectors:
[1,1] and [-1,1]
Could someone explain to be what went wrong here?

채택된 답변

Steven Lord
Steven Lord 2018년 12월 14일
However, this is not the correct answer
You're assuming there is only one correct answer. That is not a valid assumption in this case.
Multiplying the eigenvector by any non-zero scalar just scales the eigenvector, and that scaled eigenvector still satisfies the equation that eigenvectors must satisfy. This makes sense if you look at the essential definition according to Wikipedia.
"In essence, an eigenvector v of a linear transformation T is a non-zero vector that, when T is applied to it, does not change direction. Applying T to the eigenvector only scales the eigenvector by the scalar value λ, called an eigenvalue."
See this example:
% Compute eigenvalues and eigenvectors
% A = magic(6)
[V, D] = eig(A)
% Does the first eigenvalue and eigenvector satisfy A*V = V*D?
shouldBeCloseToZeroVector1 = A*V(:, 1) - V(:, 1) * D(1, 1) % Close enough
% Multiple the first eigenvector by 2
twice = 2*V(:, 1);
% Does two times the first eigenvalue and eigenvector satisfy A*V = V*D?
shouldBeCloseToZeroVector2 = A*twice - twice * D(1, 1) % Also close enough
This is not a bug.
  댓글 수: 1
holistic
holistic 2018년 12월 17일
Thank you all, I guess that slipped my mind :).

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Mark Sherstan
Mark Sherstan 2018년 12월 14일
편집: Mark Sherstan 2018년 12월 14일
The answer is correct, MATLAB is just outputting the unit vector answer.
, where i is either 1 or 2.

카테고리

Help CenterFile Exchange에서 Eigenvalues & Eigenvectors에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by