채택된 답변

madhan ravi
madhan ravi 2018년 12월 8일

1 개 추천

Lines 2 , 3 and 4 should be at the end of part a

댓글 수: 12

Abdulrahman Al Ali
Abdulrahman Al Ali 2018년 12월 8일
99.JPG
Abdulrahman Al Ali
Abdulrahman Al Ali 2018년 12월 8일
what should be done here?
madhan ravi
madhan ravi 2018년 12월 8일
) at the right side is missing
Abdulrahman Al Ali
Abdulrahman Al Ali 2018년 12월 8일
it worked but, now i got another problem
pppp.JPG
madhan ravi
madhan ravi 2018년 12월 8일
upload your code
madhan ravi
madhan ravi 2018년 12월 8일
편집: madhan ravi 2018년 12월 8일
Abdulrahman Al Ali's answer moved here for consistency:
syms ;
Qat1=subs(Qrulea,x,1);
Dat1=subs(Directa,x,1);
assert(isequal(Qat1,Dat1),
% Part a
fa= (x^2-8*x+16) ;
ga= (-3*x^2-2*x^3) ;
Qrulea= fa*diff(ga)-diff(fa)*ga/ga^2 % Use the formula above here (no semicolons so you can compare answers)
Directa= diff(fa/ga) % Just use the diff command here
% Part b
fb= sqrt(x) ;
gb= (x^2-2*x+3) ;
Qruleb= fb*diff(gb)-diff(fb)*gb/gb^2
Directb= diff(fb/gb)
madhan ravi
madhan ravi 2018년 12월 8일
Looks like you didn't even put anything like what I said then what's the use of me helping??
Abdulrahman Al Ali
Abdulrahman Al Ali 2018년 12월 8일
sorry i uploded the wrong code
syms x;
% Part a
fa= (x^2-8*x+16) ;
ga= (-3*x^2-2*x^3) ;
Qrulea= fa*diff(ga)-diff(fa)*ga/ga^2 % Use the formula above here (no semicolons so you can compare answers)
Directa= diff(fa/ga) % Just use the diff command here
Qat1=subs(Qrulea,x,1);
Dat1=subs(Directa,x,1);
assert(isequal(Qat1,Dat1)),
% Part b
fb= sqrt(x) ;
gb= (x^2-2*x+3) ;
Qruleb= fb*diff(gb)-diff(fb)*gb/gb^2
Directb= diff(fb/gb)
Qat1=subs(Qruleb,x,1);
Dat1=subs(Directb,x,1);
assert(isequal(Qat1,Dat1)),
Qrulea= (diff(fa)*ga-fa*diff(ga))/ga^2
^-----------------------^-----forgot to put parantheses DON'T FORGET ABOUT QUOTIENT RULE!!!
Abdulrahman Al Ali
Abdulrahman Al Ali 2018년 12월 8일
THANK YOU VERY MUCH!!!!!!!!!!
madhan ravi
madhan ravi 2018년 12월 8일
Anytime :)

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

질문:

2018년 12월 8일

댓글:

2018년 12월 8일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by