I am trying to solve a system of equations using fsolve but I keep getting the following error:
Unable to perform assignment because the indices on the left side are not compatible with the size of the right side.
Error in root2d (line 4)
F(1)=(m*(x1-x3))-(y1-y3);
Below is a snippet of my code, with the function first followed by the main script.
function F = root2d(k,m,x1,y1)
x3 = k(1);
y3 = k(2);
F(1)=(m*(x1-x3))-(y1-y3);
F(2)=(sqrt(((y1-k(2))^2)+((x1-k(1))^2)))-1;
m = diff(y(xx1));
x0 = [0,0];
sol = fsolve(@(k)root2d(k,m,x1,y1),x0);
Note: x1 and x2 are scalars defined earlier in the code.
Can anyone help me fix this error? Thank you!

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madhan ravi
madhan ravi 2018년 12월 5일
Dude provide the full code or attach your relevent script files
function F = root2d(k,m,x1,y1)
x3 = k(1);
y3 = k(2);
F(1)=(m*(x1-x3))-(y1-y3);
F(2)=(sqrt(((y1-k(2))^2)+((x1-k(1))^2)))-1;
r = 3;
f = 2;
x0 = 0;
x1 = -3;
x2 = 3;
y0 = 0;
y1 = x1^2;
y2 = x2^2;
rmag = sqrt(((x1-x0)^2)+((y1-y0)^2));
fi = asind(r/rmag);
thetas = 0.25;
x = x1:0.01:x2;
y = x.^2;
theta = randi([-90,90],1,1);
xx1 = (randi(length(x),1,1));
x1 = x(xx1);
y1 = y(xx1);
x2 = (sind(theta))+ x1;
f = @(y2) sqrt(((x1-x2)^2)+((y1-y2)^2))-1;
y2 = fsolve(f,1);
m = diff(y(xx1));
x0 = [0,0];
sol = fsolve(@(k)root2d(k,m,x1,y1),x0);
madhan ravi
madhan ravi 2018년 12월 5일
편집: madhan ravi 2018년 12월 5일
but before the error I get this
Equation solved. The sum of squared function values, r = 5.652814e-22, is less than
sqrt(options.FunctionTolerance) = 1.000000e-03. The relative norm of the gradient of r,
2.261198e-11, is less than options.OptimalityTolerance = 1.000000e-06.
Optimization Metric Options
relative norm(grad r) = 2.26e-11 OptimalityTolerance = 1e-06 (default)
r = 5.65e-22 sqrt(FunctionTolerance) = 1.0e-03 (default)
>>
Madhan, I don't understand your comment. I think you are missing part of your response? Thanks for the help!
Do you know how I may correct the error or why I am getting it?
I dont have error. I'm bit confusing. You should save them in one script.
function F = root2d(k,m,x1,y1)
x3 = k(1);
y3 = k(2);
F(1)=(m*(x1-x3))-(y1-y3);
F(2)=(sqrt(((y1-k(2))^2)+((x1-k(1))^2)))-1;
end
Open another script and run it :
r = 3;
f = 2;
x0 = 0;
x1 = -3;
x2 = 3;
y0 = 0;
y1 = x1^2;
y2 = x2^2;
rmag = sqrt(((x1-x0)^2)+((y1-y0)^2));
fi = asind(r/rmag);
thetas = 0.25;
x = x1:0.01:x2;
y = x.^2;
theta = randi([-90,90],1,1);
xx1 = (randi(length(x),1,1));
x1 = x(xx1);
y1 = y(xx1);
x2 = (sind(theta))+ x1;
f = @(y2) sqrt(((x1-x2)^2)+((y1-y2)^2))-1;
y2 = fsolve(f,1);
m = diff(y(xx1));
x0 = [0,0];
sol = fsolve(@(k)root2d(k,m,x1,y1),x0);
What do you mean I should save them in one script? You later said you opened another script.
I'm still getting an error.
Kevin Chng
Kevin Chng 2018년 12월 5일
Save them in the same path, and then run Untitled2.m.

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madhan ravi
madhan ravi 2018년 12월 5일
편집: madhan ravi 2018년 12월 6일

0 개 추천

Alternatively a script can contain function at the end of your script in 2016b or later
r = 3;
f = 2;
x0 = 0;
x1 = -3;
x2 = 3;
y0 = 0;
y1 = x1^2;
y2 = x2^2;
rmag = sqrt(((x1-x0)^2)+((y1-y0)^2));
fi = asind(r/rmag);
thetas = 0.25;
x = x1:0.01:x2;
y = x.^2;
theta = randi([-90,90],1,1);
xx1 = (randi(length(x),1,1));
x1 = x(xx1);
y1 = y(xx1);
x2 = (sind(theta))+ x1;
f = @(y2) sqrt(((x1-x2)^2)+((y1-y2)^2))-1;
y2 = fsolve(f,1);
m = diff(y(xx1));
x0 = [0,0];
sol = fsolve(@(k)root2d(k,m,x1,y1),x0); % function call
function F = root2d(k,m,x1,y1) % function definition
x3 = k(1);
y3 = k(2);
F=[(m*(x1-x3))-(y1-y3); %changed this line and the error was avoided
(sqrt(((y1-k(2))^2)+((x1-k(1))^2)))-1];
end

댓글 수: 2

This worked, thank you so much!
madhan ravi
madhan ravi 2018년 12월 6일
편집: madhan ravi 2018년 12월 6일
Anytime :)

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