필터 지우기
필터 지우기

for loop to matrix calculation

조회 수: 1 (최근 30일)
john_arle
john_arle 2018년 12월 3일
댓글: Jan 2018년 12월 4일
Hello there,
I do not know how to optimize this calculation. It is very slow, since vector "my_vector" is made of 3 millions indeces.
I would like to perform the same calculation using matrices, but I really do not know how to do it!
Thank you!
Have a good one,
Andrea.
corr = zeros(1,n_A*p_A-1); % row vector of 3762799
v = residual(my_vector);
variance = mean(v.^2);
index_corr = 0;
ref_length = 0;
for l = 1:(n_A*p_A-1)
for j = 1:(n_A*p_A-l)
corr(1,l) = corr(1,l)+v(1,j)*v(1,j+l);
end
corr(1,l) = corr(1,l)/((n_A*p_A-l)*variance);
if (corr(1,l) < (1/exp(1)))
if index_corr == 0
ref_length = l;
end
index_corr = 1;
end
end
  댓글 수: 1
Jan
Jan 2018년 12월 3일
편집: Jan 2018년 12월 3일
It would be useful if you explain, what the code should do. Some meaningful comments in the code are required also to improve its quality. Please provide some meaningful inputs also, because this is more efficient than letting the readers guess the inputs.

댓글을 달려면 로그인하십시오.

채택된 답변

Jan
Jan 2018년 12월 3일
편집: Jan 2018년 12월 3일
1/exp(1) is a very expensive calculation. Do this once before the loop.
The index "l" (lowercase L) looks like a "1", so I replaced it by "k".
corr = zeros(1, n_A*p_A-1); % row vector of 3762799
v = residual(my_vector);
variance = mean(v .^ 2);
index_corr = 0;
ref_length = 0;
c = 1 / exp(1);
for k = 1:(n_A*p_A-1)
n = n_A * p_A - k;
% Use DOT product to calculate the sum:
corr(1, k) = corr(1, k) + v(1, 1:n) * v(1, (1 + k):(n + k)).';
% Alternative - assumed to be slower:
% corr(1, k) = corr(1, k) + sum(v(1, 1:n) .* v(1, (1 + k):(n + k)));
corr(1, k) = corr(1,k) / ((n_A*p_A-k) * variance);
if corr(1,k) < c
if index_corr == 0
ref_length = k;
end
index_corr = 1;
end
end
  댓글 수: 3
john_arle
john_arle 2018년 12월 4일
Hello Jan,
thank you again for your kind response!
I get an error though (implementing dot product), and I do not know how to fix it!
Index in position 2 exceeds array bounds (must not exceed 1).
Error in example2 (line 67)
corr(1, k) = corr(1, k) + v(1, 1:n) * v(1, (1 + k):(n + k)).';
Jan
Jan 2018년 12월 4일
@Andrea: Unfortunately I cannot run your code, because you did not provide the input arguments. Then you have to debug the code by your own. Perhaps one of the inputs is a column vector? Try this:
...
v = V(:).';
for k = 1:(n_A*p_A-1)
n = n_A * p_A - k;
corr(k) = corr(k) + v(1:n) * v((1 + k):(n + k)).';
corr(k) = corr(k) / ((n_A*p_A-k) * variance);
if corr(k) < c
if index_corr == 0
ref_length = k;
end
index_corr = 1;
end
end

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Matrix Indexing에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by