how I do it. the function is called a string is passes a numbr
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how could I do this one
looks like
functionname('hello')
ans= hello1
functionname('john')
ans= john2
...
many thanks
댓글 수: 1
dpb
2018년 11월 19일
Which number, in particular? Any one, random, user-specified, sequential since last invocation as shown above (requires some extra logic to keep track of that and over what population if so)...???
So many questions, so little known... :)
s=sprintf('%s%d',str,randi(1000);
might give you some ideas, however...
채택된 답변
Stephen23
2018년 11월 20일
function out = myfun(inp)
persistent cnt
if nargin==0 || isempty(cnt)
cnt = 0;
end
cnt = cnt+1;
assert(cnt<=5,'You already have five words')
out = sprintf('%s%d',inp,cnt);
end
And tested:
>> myfun('anna')
ans = anna1
>> myfun('bob')
ans = bob2
>> myfun('cathy')
ans = cathy3
>> myfun('david')
ans = david4
>> myfun('evalyn')
ans = evalyn5
>> myfun('frog')
error: You already have five words
추가 답변 (2개)
Luna
2018년 11월 20일
Hello Dezdi,
You can do it by first collecting your inputs in a cell array and then call your function in a for loop with 5 elements.
inputStr = {'John','Mary','Kayle','Adam','David'};
for i = 1:5
out = myFunc(inputStr,i)
end
function outputStr = myFunc(inputStr,i)
outputStr = [inputStr{i}, sprintf('%d',i)];
end
Preethi
2018년 11월 20일
hi,
check this
function test_preethi(str)
persistent i
if isempty(i)
i=1;
else
if i <=5
sprintf('%s%d',str,i)
i=i+1 ;
else
sprintf('limit reached')
end
end
댓글 수: 3
dpb
2018년 11월 20일
This particular function only "works" in that it creates the string internal to the function but you can't get at the result.
The use of persistent is good in saving the previous value, unfortunately the function has no mechanism by which the variable can be reset/re-initialized so without external intervention once the sequence is full, there's no going forward...details, details! :)
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