How do we write a code for a periodic intermittent scalar function?

I would like to write a code of an periodic intermittent bounded control. I've tried to write it as a piecewise function but its not giving me type of output I want. Can someone help please? This what I have written
K = 0:0.01:1;
Pk =[];
m = 4; h = 0.1; T = 0.05;
for k = 1:length(K)
if (K(k) >= m*T & K(k) < m*T + h)
pk = 4;
elseif (K(k) >= m*T + h & K(k) < (m+1)*T)
pk = 0;
end
Pk = [Pk pk];
end

댓글 수: 4

you need to explain what result you are expecting and why do you think the above code is wrong
This what it is giving me.
However, I want something like this
And what do you expect instead?

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 채택된 답변

Eric Mwanandiye
Eric Mwanandiye 2018년 11월 29일

0 개 추천

Here is what I wanted. I've solved it.
clear all; close all; clc;
N = 0.2;
h = 0.5;
n= 0:25;
t = 0:0.001:5;
for i = 1:length(n)
for j = 1:length(t)
if (t(j) >= n(i)*N)&(t(j) < (n(i) + h)*N)
k(j) = 2;
elseif (t(j) >= (n(i) + h)*N)&(t(j) < (n(i) + 1)*N)
k(j) = 0;
end
end
end
plot(t,k,'linewidth',2)
axis([0 5 0 2.5]);

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카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

질문:

2018년 11월 9일

답변:

2018년 11월 29일

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