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Collision Problem (Square 2d)

조회 수: 1 (최근 30일)
Jake Simmonds
Jake Simmonds 2018년 11월 2일
댓글: aliyah islam 2019년 12월 18일
Hello there, i am trying to write some code that plots a square moving along a line with a certain velocity when the centre of the squares coordinates get within a certain tolerance the direction of the velocity becomes negative and so it 'bounces' off the wall. My code is below but the constraints in terms of direction don't seem to be working any insight would be greatly appreciated. Best Regards
fps = 20;
dt = 1/fps;
tmax = 10;
t = 0;
theta = 0;
dtheta = 1/20;
p = transpose([20,20,1]);
v = transpose([50,25,1]);
Vobj = transpose([2, -2, 1; 2,2,1; -2, 2, 1; -2, -2, 1]);
while t < tmax
x = p + t*v;
if x(1)<= 5 || x(1) >= 95
v(1)=-v(1);
elseif x(2)<= 5 || x(2) >= 95
v(2)=-v(2);
end
p = x;
% Transformations
T = [1,0,p(1);0,1,p(2);0,0,1];
S = [1+0.2*sin(2*t),0,0; 0,1+0.2*sin(2*t),0;0,0,1];
R = [cos(theta),sin(theta),0 ;-sin(theta),cos(theta),0;0,0,1];
% Application of Transformations
V = R*S*T*Vobj;
fill(V(1,:),V(2,:),'r')
hold on
axis([0,100,0,100])
hold off
shg;
pause(0.3);
% Updates
t = t + dt;
theta = theta + dtheta;
end
  댓글 수: 1
aliyah islam
aliyah islam 2019년 12월 18일
Did you end up figuring this problem out? If so have you still got the matlab code for it, as i have a similar problem to solve. Thanks

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답변 (1개)

madhan ravi
madhan ravi 2018년 11월 2일
fps = 20;
dt = 1/fps;
tmax = 10;
t = 0;
x =[20,20,1];
v = [50,25,1];
ctr=1;
while t < tmax
p(ctr,:) = x + t*v;
if p(1) < 5 || p(1) > 95 || p(2) < 5 || p(2) > 95
p(ctr,:) = x + t*(-v);
else
p(ctr,:) = x + t*v;
end
plot(p(1),p(2),'o')
hold on
axis([0,100,0,100])
hold off
pause(1);
t = t + dt;
end
  댓글 수: 3
Jake Simmonds
Jake Simmonds 2018년 11월 2일
This still has the same issue as my above code once it enters the tolerance it just disappears
Jake Simmonds
Jake Simmonds 2018년 11월 2일
It's a matter of changing the direction the plot goes after it is in the critical zone so to speak.

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