Computing the integral of a binary image
조회 수: 4 (최근 30일)
이전 댓글 표시
Hello fellows:
I am trying to figure out how to compute the integral of the square of the difference between 2 images. So far I know that I have to convert the image to a binary one, but in order to compute the integral I am thinking of plotting the profile of the intensity values of each image than subtract one from another and integrate after I square the result. What do you think about that methodology? If it is wrong or you have a better one can you share keywords for the approach to do that?
댓글 수: 0
채택된 답변
Walter Roberson
2012년 7월 2일
The integral of the square of the difference between two binary images is
sum(BinaryImage1(:) ~= BinaryImage2(:))
That is:
0 - 0 = 0; 0^2 = 0; and (0 ~= 0) = 0
0 - 1 = -1; (-1)^2 = 1; and (0 ~= 1) = 1
1 - 0 = 1; 1^2 = 1; and (1 ~= 0) = 1
1 - 1 = 0; 0^2 = 0; and (1 ~= 1) = 0
and thus the square of the difference is the same as ~= of the values.
댓글 수: 2
Sean de Wolski
2012년 7월 2일
@Star Strider: yup:
xor([1 1 0 0],[0 1 1 0])
ne([1 1 0 0],[0 1 1 0])
추가 답변 (1개)
Image Analyst
2012년 7월 2일
Sounds like you just want the RMS difference between the two images, so I guess I don't understand why you think you must convert the images to binary images, or why " plotting the profile" is necessary. For gray scale images, why not just do
rmsDifference = sqrt(sum((double(grayImage1(:)) - double(grayImage2(:))) .^2));
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Convert Image Type에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!